We know there’s a change in momentum due to a force applied over a time interval. Ft= m[v(final)-v(initial)]. Now simply plug in know values: (45)(0.02)=.005[v(final)-0]. Remember converting grams to kilograms. Solve for v final
Answer:
A mixture of blue & red light.
Explanation:
During photosynthesis, the oxygen delivered emanates from water particles and if a weighty isotope of oxygen atom was noticed in delivered sub-atomic oxygen, the water atoms were marked with the hefty isotope.
In order to maximize the growth rate of the plant, the required wavelength of light to be used is a mixture of blue & red light. This is on the grounds that as the absorption optima of plant's photoreceptors are at wavelength frequency of red and blue light, subsequently the combination of red and blue light would be ideal for plant growth and development.
The productivity of red (650–665 nm) LEDs on plant development is straightforward on the grounds that these wavelength frequencies entirely fit with the retention pinnacle of chlorophylls and phytochrome, while the enhanced blue light presented the possibility that development under regular light could be mirrored utilizing blue and red LEDs with negligible use of energy.
F= ma
F= (600/-10) -10
F= 580n
At least I think that’s the answer
Answer:
a. True
Explanation:
Illumination distance is the distance, up to which the light of the vehicle can reach. Hence, it is a maximum distance from the, that driver can see.
Stopping distance is the minimum distance required by the car to stop after brakes are applied.
So, in order to avoid any accident the illumination distance must be greater than the stopping distance. So, the driver can stop the vehicle in time, when he sees something in front of it.
Since, the stopping distance in this case is two or three times longer than illumination distance. Therefore, low beam light does not provide enough visibility in high speed driving situations.
Hence, the correct option is:
<u>a. True</u>
<u></u>
The best conclusion that can be drawn is that D) A current does not flow in the wire
