Question

Two point charges of 20. 0 μc and -8. 00 μc are separated by a distance of 20. 0 cm. what is the intensity of electric field e midway between these two charges? group of answer choices

Answer 1

The intensity of electric field E midway between these two charges is 2.52*10^7N/C.

To find the answer, we have to know more about the electric field.

How to find the electric field?

• We have the expression for net electric field as,

                      $E=\frac{kQ}{r^2}$

where, k is the constant equal to 8.99*10^9.

• Thus, we can write the electric field created by 20micro coulomb charge at the midway between two charges is,

                $E_1=\frac{8.99*10^9*20*10^{-6}}{10*10^{-2}} =1.79*10^7N/C$

• We can write the electric field created by -8micro coulomb charge at the midway between two charges is,

                 $E_2=\frac{8.99*10^9*8*10^{-6}}{(10*10^{-2})^2} =7.19*10^6N/C$

• Thus, the net field at the midway due to two charges will be,

                $E=1.79*10^7+7.19*10^6=2.52*10^7N/C$

Thus, we can conclude that, the intensity of electric field e midway between these two charges is 2.52*10^7N/C.

Learn more about the electric field here:

brainly.com/question/27752270

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