Question

an object has a constant acceleration of 3.2 m/s^2.at a certain instant its velocity is 10 m/s . what is its velocity after 5 sec

Answer 1

So here, you're looking for distance. The formula is D=vt+1/2at^2.

Lets plug in the informations.

10 m/s is our v (initial velocity)

5 second is out t(time)

3.2 m/s is our a(acceleration)

10m/s(5)+1/2(3.2m/s+5^2)

50m/s+1/2(28.2)

50m/s+14.1

Answer =64.1 m

Glad to help you out buddy. Let me know if you need help.