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3 years ago

The unit for measuring electric power is the

Physics

1 answer:

bazaltina [42]3 years ago

4 0

C.) The measuring unit of "Electrical Power" is "Watt"

Hope this helps!

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A .5kg bird is perched on its nest so that it has 50J of potential energy. how far is it off the of the ground?

pshichka [43]

It is 10.20 m from the ground.

<u>Explanation:</u>

<u>Given:</u>

m = 0.5 kg

PE = 50 J

We know that the Potential energy is calculated by the formula:

$P. E = m \times g \times h$

where m is the is mass in kg; g is acceleration due to gravity which is 9.8 m/s and h is height in meters.

PE is the Potential Energy.

Potential Energy is the amount of energy stored when an object is stationary.

Here, if we substitute the values in the formula, we get

$P. E = m \times g \times h$

50 = 0.5 × 9.8 × h

50 = 4.9 × h

$h = \frac {50} {4.9}$

h = 10.20 m

3 0

3 years ago

How do i figure out this question?

nikklg [1K]

Answer:

0.75 g/cm^3

Explanation:

The formula for density:

$\rho = \frac{m}{V}$

Where m is the mass and V is the volume.

So, we can substitute values for m and V:

$\rho = \frac{277}{370}\approx0.75$

Therefore, the density is 0.75 g/cm^3 (watch the units!)

8 0

3 years ago

Read 2 more answers

You drop a ball from a height of 2.0 m, and it bounces back to a height of 1.5 m. a) What fraction of its initial energy is lost

tangare [24]

The fraction of energy that is lost is 25%, it depends how fast the ball was going until it lost 25% of its energy, the gravitational energy was transferred into the kinetic energy that helped the ball bounce back

4 0

3 years ago

During heavy rain, a section of a mountainside measuring 2.5 km horizontally, 0.80 km up along the slope, and 2.0 m deep slips i

Crank

Answer:

The mass of the mud is 3040000 kg.

Explanation:

Given that,

length = 2.5 km

Width = 0.80 km

Height = 2.0 m

Length of valley = 0.40 km

Width of valley = 0.40 km

Density = 1900 Kg/m³

Area = 4.0 m²

We need to calculate the mass of the mud

Using formula of density

$\rho=\dfrac{m}{V}$

$m=\rho\times V$

Where, V = volume of mud

$\rho$ = density of mud

Put the value into the formula

$m=1900\times4.0\times0.40\times10^{3}$

$m =3040000\ kg$

Hence, The mass of the mud is 3040000 kg.

4 0

3 years ago

How did the magnet’s density measurement using the Archimedes’ Principle compare to the density measurement using the calculated

guapka [62]

Answer:

The two methods will yield different results as one is subject to experimental errors that us the Archimedes method of measurement, the the density measurement method will be more accurate

Explanation:

This is because the density method using the calculated volume will huve room for less errors that's occur in practical method i.e Archimedes method due to human error

5 0

3 years ago