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Law Incorporation [45]
4 years ago
8

If a stone with an original velocity was of 0 Is falling from a ledge and takes 8 seconds to hit the ground what is the final ve

locity of the stone
Physics
1 answer:
Llana [10]4 years ago
3 0
A=(v-u)/t
10=v/8
v=80(unit)
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Two point charges are brought closer together, increasing the force between them by a factor of 20. By what factor was their sep
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The separation between them is \frac{r}{\sqrt{20} }

Concept :

If the force increases, distance between charges must decrease. Force is indirectly proportional to the distance squared.

Given,

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F = \frac{kq_{1} q_{2} }{r^{2} } -------- ( 1 )

Here, q_{1} , q_{2} are charges and r is the distance between them

New force F' = \frac{kq_{1q_{2} } }{r'^{2} } ----------- (2 )

Divide ( 1 ) and ( 2 )

\frac{F'}{F} = \frac{\frac{kq_{1}q_{2}  }{r'^{2} } }{\frac{kq_{1}_{2}  }{r^{2} } }

20 = \frac{r^{2} }{r'^{2} }

r' = \frac{r}{\sqrt{20} }

Given that force between them are increasing and therefore distance between them decrease by \frac{r}{\sqrt{20} }

Learn more about two point charges here : brainly.com/question/24206363

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