What is a valence electron

Reacting Solutions of Aluminum Chloride with Potassium Hydroxide

1Al2(SO4)3 + 3ZnCl2 → 2AlCl3 + 3ZnSO4

The coefficients represents moles. There is 1 mole of Aluminum Sulfate, 3 moles of Zinc(II) Chloride, 2 moles of Aluminum Chloride, and 3 moles of Zinc(II) Sulfate.

Now add all the coefficients/moles.

9 is the sum of all the coefficients.

7 0

3 years ago

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Determine the empirical formulas for compounds with the following percent compositions:

White raven [17]

Answer: a) $CS_2$

b) $CH_2O$

Explanation:

a) If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C = 15.8g

Mass of S= 84.2 g

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{15.8g}{12g/mole}=1.32moles$

Moles of S= $\frac{\text{ given mass of S}}{\text{ molar mass of S}}= \frac{84.2g}{32g/mole}=2.63moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{1.32}{1.32}=1$

For S = $\frac{2.63}{1.32}=2$

The ratio of C : S = 1:2

Hence the empirical formula is $CS_2$

b) Mass of C= 40 g

Mass of H= 6.7 g

Mass of O = 53.3 g

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{40g}{12g/mole}=3.33moles$

Moles of H = $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{6.7g}{1g/mole}=6.7moles$

Moles of O = $\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{53.3g}{16g/mole}=3.33moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{3.33}{3.33}=1$

For H = $\frac{6.7}{3.33}=2$

For O = $\frac{3.33}{3.33}=1$

The ratio of C : H: O= 1 :2: 1

Hence the empirical formula is $CH_2O$

5 0

3 years ago

What is the formula and name of the compound produced at the end of the virtual lab, and what caused it to have a different appe

Iteru [2.4K]

Answer: $SnO_2$ , $NO_2$ and $H_2O$ are formed at the end of the reaction. They are named as tin (IV) oxide or stannic oxide, nitrogen dioxide and water respectively.

Explanation: Reaction of tin and nitric acid is given as:

$Sn(s)+4HNO_3(aq.)\rightarrow SnO_2(s)+4NO_2(g)+2H_2O(l)$

Three products are formed at the end of the reaction which are:

$SnO_2$ which is termed as stannic oxide or Tin (IV) oxide. This is a white colored solid.

$NO_2$ which is termed as nitrogen dioxide. These are brown colored fumes.

$H_2O$ which is termed as water.

At the starting tin was a silvery-white colored solid and after the reaction, it changed the color to milky-white. This change in color is due to the chemical reaction happening between tin and nitric acid.

Release of brown fumes are also an indication that a chemical reaction has taken place.

6 0

3 years ago

Every ________ will have its own unique set of quantum numbers.

yulyashka [42]

Answer:

D. individual electron

Explanation:

7 0

3 years ago

Methylation is a process that involves which of the following metals

Vesnalui [34]

Methylation is a process that involves Mercury metal. Methylation is a process by which a methyl groups are added to the DNA molecule. when it occurs it can change the activity of a DNA segment without changing the sequence, additionally, when located in a gene promoter it may act to repress gene transcription.

7 0

4 years ago