When palmitate (C16) completely oxidized, net yield is 129 ATP.
There are 7 β-oxidation cycles for palmitate to completely oxidazed.
One β-oxidation (beta-oxidation) cycle produces 1 NADH, 1 FADH2, and 1 acetyl CoA (sea the picture below).
For 7 cycles: 7 NADH, 7 FADH2, and 8 acetyl CoA.
NADH and FADH2 enter Electron Transport System (ETS) cycle to generate 3ATP and 2ATP respectively.
Acetyl CoA enter into tricarboxylic acid cycle (TCA) and each CoA gives 12 ATP.
7 NADH = 7 x 3 = 21 ATP
7 FADH2 = 7 x 2 = 14 ATP
8 acetyl-CoA = 8 x 12 = 96 ATP
Net yield of ATP = 21 ATP + 14 ATP + 96 ATP - 2 ATP (used during conversion of palmitic acid into palmitoyl CoA)
Net yield of ATP = 129 ATP
More about beta-oxidation: brainly.com/question/14993930
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Answer:
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Formula : BaI₂. <span>barium iodide</span>
From the balanced equation 2KClO3 → 2KCl + 3O2, the coefficients are the following:
coefficient 2 in front of potassium chlorate KClO3
coefficient 2 in front of potassium chloride KCl
coefficient 3 in front of oxygen molecule O2
We got this balanced equation by identifying the number of atoms of each element that we have in the given equation KClO3 → KCl + O2.
Looking at the subscripts of each atom on the reactant side and on the product side, we have
KClO3 → KCl + O2
K=1 K=1
Cl=1 Cl=1
O=3 O=2
We can see that the oxygens are not balanced. We add a coefficient 2 to the 3 oxygen atoms on the left side and another coefficient 3 to the 2 oxygen
atoms on the right side to balance the oxygens:
2KClO3 → KCl + 3O2
The coefficient 2 in front of potassium chlorate KClO3 multiplied by the subscript 3 of the oxygen atoms on the left side indicates 6 oxygen atoms just as the coefficient 3 multiplied by the subscript 2 on the right side indicates 6 oxygen atoms.
The number of potassium K atoms and chloride Cl atoms have changed as well:
2KClO3 → KCl + 3O2
K=2 K=1
Cl=2 Cl=1
O=6 O=6
We now have two potassium K atoms and two chloride Cl atoms on the reactant side, so we add a coefficient 2 to the potassium chloride KCl on the product side:
2KClO3 → 2KCl + 3O2, which is our final balanced equation.
K=2 K=2
Cl=2 Cl=2
O=6 O=6
The potassium, chlorine, and oxygen atoms are now balanced.
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