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REY [17]
2 years ago
12

Iron is more elastic than rubber . Give reason.

Physics
1 answer:
Arisa [49]2 years ago
8 0

The deforming force increases as you pull harder, and the rubber band may break, but the iron rod will not. As a result, rubber has less elasticity than iron.

<h3 /><h3>What is elasticity?</h3>

A body's ability to regain its former shape after being subjected to external deforming pressures is known as elasticity.

If you pull harder, the deforming force will rise and the rubber band may break, but the iron rod won't. As a result, we may say that rubber is less elastic than iron.

Hence, iron is more elastic than rubber.

To learn more about the elasticity refer to:

brainly.com/question/14450755

#SPJ1

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As plates move, large blocks of crust ___ along the faults
seraphim [82]

Answer:

move

Explanation:

i think that is it

as plates move large blocks of crust move along the faults

4 0
3 years ago
Question 10 of 34
labwork [276]

Julia walks from the park, which is six blocks east of her house, to the store, which is three blocks east of her house. Julia walks for 5 minutes. This walk's average speed will be 1.2 blocks per minute. Option B is correct.

<h3>What is displacement?</h3>

Displacement is defined as the shortest distance between the two points. Distance is the horizontal length covered by the body. While displacement is the shortest distance between the two points.

Displacement is a vector quantity .its unit is m.

The average velocity on this walk will be;

\rm v_{avg}= \frac{d}{t} \\\\ \rm v_{avg}= \frac{6 \ block+ 3 \ block }{5 \ minute } \\\\ v_{avg}=1.4  \ block /min

Hence option B is correct.

To learn more about displacement refer to the link; brainly.com/question/10919017

#SPJ1

3 0
2 years ago
A 4 kg block is launched up a 30° ramp with an initial speed of 5 m/s. The coefficient of kinetic friction between the block and
zlopas [31]

Answer:

The speed of the block when it has returned to the bottom of the ramp is 6.56 m/s.

Explanation:

Given;

mass of block, m =  4 kg

coefficient of kinetic friction, μk = 0.25

angle of inclination, θ = 30°

initial speed of the block, u = 5 m/s

From Newton's second law of motion;

F = ma

a = F/m

Net horizontal force;

∑F = mgsinθ + μkmgcosθ

a = \frac{F_{NET}}{m} = \frac{mgsin \theta + \mu_kmgcos \theta}{m} \\\\a = gsin \theta + \mu_kgcos \theta\\\\a = 9.8sin (30) + 0.25*9.8cos(30)\\\\a = 4.9 + 2.1217\\\\a = 7.022 \ m/s^2

At the  top of the ramp, energy is conserved;

Kinetic energy = potential energy

¹/₂mv² = mgh

¹/₂ v² = gh

¹/₂ x 5² = 9.8h

12.5 = 9.8h

h = 12.5/9.8

h = 1.28 m

Height of the ramp is 1.28 m

Now, calculate the speed of the block (in m/s) when it has returned to the bottom of the ramp;

v² = u² + 2ah

v²  = 5² + 2 x 7.022 x 1.28

v²  = 25 + 17.976

v²  = 42.976

v = √42.976

v = 6.56 m/s

Therefore, the speed of the block when it has returned to the bottom of the ramp is 6.56 m/s.

4 0
4 years ago
Why do blades come in different lengths in a jig saw sander?​
trasher [3.6K]

Answer:

To determine the minimum blade length, add 1" to the workpiece thickness. One type of material, and some materials can be cut by more than one type of blade. No matter the material, there's likely a jigsaw blade designed specifically for. Armed with the right blade, follow these pointers to make your work go (and cut) .

Explanation:

6 0
3 years ago
How much work is done by a student carrying a 12 kg backpack while accelerating at a rate of 0.51 m/s2 over a distance of 5.0 m?
Klio2033 [76]

The amount of work done by the student in carrying the backpack is 30.6 J

<h3>Definition of workdone </h3>

Workdone is defined as the product of force and distance moved in the direction of the force.

Work done (Wd) = Force (F) × distance (d)

Wd = Fd

Also,

Force (F) = mass (m) × acceleration (a)

F = ma

Therefore,

Wd = (ma) × d

With the above formula, we can obtain the work done by the student.

<h3>How to determine the Workdone </h3>

From the question given above, the following data were obtained:

  • Mass (m) = 12 Kg
  • Acceleration (a) = 0.51 m/s²
  • Distance (d) = 5 m
  • Workdone (Wd) =?

Wd = (ma) × d

Wd = 12 × 0.51 × 5

Wd = 30.6 J

Learn more about workdone:

brainly.com/question/14667371

8 0
3 years ago
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