Answer:
The force becomes 16 times what it is now.
Explanation:
The formula for gravitational force is
F = G * m1 * m2 / r^2
When you do what you have described, you are setting a stage that not even the USS Enterprise (Star Trek) can get out of. The increase is huge.
If you double m1 and m2 and don't do anything to r, you've already increased the force by 4 times. (2m1 * 2m2 = 4 * m1 * m2)
But you are not finished. If you 1/2 the distance, you are again increasing the Force by 4 times. 1 / (2r) ^2 = 1/ 4* r^2
Because this is in the denominator, the 1/4 is going to flip to the numerator.
So the total increase is going to be 4 * (4 * m1 * m2) = 16 * m1 * m2.
Think about what that means. If you were out golfing, your drives would be roughly 1/16 times as far as they are now. Also you would be lugging around 16 times your weight around the golf course. My feeling is that you would never finish 5 holes at that rate.
Answer:
V = 42.41cm^3
Explanation:
In order to calculate the volume of the solid, you use the following formula:
where
r: radius of the circular base of the cone = 3 cm
h: height from the circular base to the peak of the cone = 4.5 cm
You replace the values of r and h in the formula for the volume V:
hence, the volume of the solid is 42.41 cm^3
Answer:
Explanation:
initial velocity v = 2.1 x 10⁷ m/s
acceleration a = 5.1 x 10¹⁵ m /s²
horizontal distance covered = 5.5 x 10⁻² m
time taken to cover horizontal distance = 5.5 x 10⁻² / 2.1 x 10⁷
= 2.62 x 10⁻⁹ s .
b )
vertical distance travelled due to vertical acceleration
= 1/2 a t²
= .5 x 5.1 x 10¹⁵ x (2.62 x 10⁻⁹)²
= 17.5 x 10⁻³ m
××
×
50N is your force and the acceleration is -9.8m/s^2 due to gravity.
So, you just plug that in.
BUT you know that mass cannot be negative, so you just disregard the negative sign and the mass of the rock is 5.102 grams.
Answer:
121550 J
Explanation:
Parameters given:
Mass, m = 0.34kg
Specific heat capacity, c = 14300 J/kgK
Change in temperature, ΔT = 25K
Heat gained/lost by an object is given as:
Q = mcΔT
Since ΔT is positive in this case and also because we're told that heat was transferred to the hydrogen sample, the hydrogen sample gained heat. Therefore, Q:
Q = 0.34 * 14300 * 25
Q = 121550J or 121.55 kJ
