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3 years ago

If two objects collid and one is initially at rest, is it possible for both to be at rest after the collision?

Physics

1 answer:

Ludmilka [50]3 years ago

5 0

Answer:

<em>Is it NOT possible for both particles to be at rest after the collision</em>

Explanation:

<u>Law Of Conservation Of Linear Momentum</u>

The total linear momentum of a system of particles is conserved regardless of their internal interactions while no external force is applied to the system. If $m_1$ and $m_2$ are the masses of two particles, and only one of them is at rest, there is a non-zero total linear momentum, i.e.

$P_1=m_1v_1+m_2v_2$

if at least one of the speeds is not zero, the total initial linear momentum is not zero.

If after the collision, both particles remain at rest, both speeds will be zero and the total linear momentum won't be conserved.

So, is it NOT possible for both particles to be at rest after the collision

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A conductor carrying a current I = 16.5 A is directed along the positive x axis and perpendicular to a uniform magnetic field. A

Jet001 [13]

To solve this problem we will apply the concepts related to the Magnetic Force, this is given by the product between the current, the body length, the magnetic field and the angle between the force and the magnetic field, mathematically that is,

$F = ILBsin \theta$

Here,

I = Current

L = Length

B = Magnetic Field

$\theta$ = Angle between Force and Magnetic Field

But $\theta = 90\°$

$F = ILB$

Rearranging to find the Magnetic Field,

$B = \frac{F}{IL}$

Here the force per unit length,

$B = \frac{1}{I}\frac{F}{L}$

Replacing with our values,

$B = \frac{0.130N/m}{16.5}$

$B = 0.0078T$

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3 years ago

Brownian motion is due to:

My name is Ann [436]

Answer:

Explanation:

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3 years ago

A potential energy function is given by u(x)=(3.00n)xâ(1.00n/m2)x3. at what position or positions is the force equal to zero?

qwelly [4]

I believe the correct form of the energy function is:

u (x) = (3.00 N) x + (1.00 N / m^2) x^3

or in simpler terms without the units:

u (x) = 3 x + x^3

Since the highest degree is power of 3, therefore there are two roots or solutions of the equation.

Since we are to find for the positions x in which the force equal to zero, u (x) = 0, therefore:

3 x + x^3 = u (x)

3 x + x^3 = 0

Taking out x:

x (3 + x^2) = 0

So one of the factors is x = 0.

Finding for the other two factors, we divide the two sides by x and giving us:

x^2 + 3 = 0

x^2 = - 3

x = sqrt (- 3)

x = - 1.732 i, 1.732 i

The other two roots are imaginary therefore the force is only equal to zero when the position is also zero.

Answer:

x = 0

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3 years ago

How many electron pairs does chlorine have?

I am Lyosha [343]

Answer:

10- in 5 pairs

Explanation:

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3 years ago

The cable of a crane is lifting a 950 kg girder. The girder increases its speed from 0.25 m/s to 0.75 m/sin a distance of 5.5m

Umnica [9.8K]

Explanation:

a) How much work is done by gravity?

w = f x d
w = 950 x 10 x 5.5 = 52250j

b) How much work is done by tension?

v²=u²+2as
0.75²=0.25²+2a x5.5
0.56=0.06+2a x5.5
2a x5.5 = 0.56 - 0.06
2a x 5.5 =0.5
11a=0.5
a = 0.5/11 = 0.05m/s²

w = f x d

w = 950 x 0.05 x 5.5 = 261.25j

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3 years ago