If the angle is either 0 or 180, that means that there is either negative or positive work, so A and D are not correct.
If the angle is 45, then there is still some work involved.
The only option where there is no work done by a force is B. when the angle is between the force and displacement is 90.
Bella’s average velocity is about 0.693 meters per second.
To find the average velocity, you must divide the distance by the change in time, which should look like v=d/t
Here is how you set up the equation-
v=6.1/8.8
Once you divide 6.1 meters by 8.8 seconds, you should get a number that looks like 0.69318182.... however, I just rounded it to 0.693 meters per second. You can round it to whatever you like.
Hope this helped! If you have any questions about what I mentioned in my answer or explanation, feel free to comment on my answer and I’ll try to get back to you!
Explanation:
700N right
to get the net force
you gotta let one direction be the negative ( the smaller force)
so the total force towards the left is 100N ( 60 + 40= 100)
which is smaller than the right force which is 800 N so you let 100 N be negative
so without even calculating , you can know that it will be moving towards the right because right force > left force
your add both forces ( remember 100 N is negative)
so 800N + ( - 100N)
= 700N
towards the right
hope this helps
this is just one method that helped me understand
please mark it brainliest
How might a suit of armor be a good analogy for a function of the skeletal system?
It's a frame for your body and protects organs and armor protects your body from injury
According to the description given in the photo, the attached figure represents the problem graphically for the Atwood machine.
To solve this problem we must apply the concept related to the conservation of energy theorem.
PART A ) For energy conservation the initial kinetic and potential energy will be the same as the final kinetic and potential energy, so



PART B) Replacing the values given as,




Therefore the speed of the masses would be 1.8486m/s