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Crazy boy [7]
3 years ago
5

The probability of drawing a heart from a standard deck of 52 playing cards is 1 4 . The probability of drawing a face card from

a standard deck of 52 playing cards is 3 13 . Based on this, Drew determines that the probability of drawing a heart face card is 3 52 . Is this correct? A) Yes, Drawing a heart and drawing a face card are independent events, so P(H ∩ F) = P(H)·P(F) = 1 4 · 3 13 = 3 52 . B) No, Drawing a heart and drawing a face card are independent events, so P(H U F) = P(H) + P(F) = 1 4 + 3 13 = 25 52 . C) No, Drawing a heart and drawing a face card are independent events, so P(H U F) = P(H) + P(F) - P(H ∩ F) = 1 4 + 3 13 - 3 52 = 11 26 . D) No, Drawing a heart and drawing a face card are dependent events, so the P(H ∩ F) = P(H)·P(F|H) = 1 4 · 3 52 + 1 4 · 2 51 = 5 204 .
Mathematics
2 answers:
hoa [83]3 years ago
8 0
We need Probability of drawing a heart Or drawing a face card other than a heart. 

This is 1/4 + 9/52  = 11/26
C is the correct choice.
Kipish [7]3 years ago
5 0
A) Yes, Drawing a heart and drawing a face card are independent events, so P(H ∩ F) = P(H)·P(F) = 1 4 · 3 13 = 3 52
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PLEASE HELP!!!!!!!!!!!!!!
Lelechka [254]

Answer:

Step-by-step explanation:

(8x²-18x+10)/(x²+5)(x-3)

express the expression as a partial fraction:

(8x²-18x+10)/[(x^2+5)(x-3)] =A/x-3 +bx+c/x²+5

both denominator are equal , so require only work with the nominator

(8x²-18x+10)=(x²+5)A+(x-3)(bx+c)

8x²-18x+10= x²A+5A+bx²+cx-3bx-3c

combine like terms:

x²(A+b)+x(-3b+c)+5A-3c

(8x²-18x+10)

looking at the equation

A+b=8

-3b+c=-18

5A-3c=10

solve for A,b and c (system of equation)

A=2 , B=6, and C=0

substitute in the value of A, b and c

(8x²-18x+10)/[(x^2+5)(x-3)] =A/x-3 +(bx+c)/x²+5

(8x²-18x+10)/[(x^2+5)(x-3)] = 2/x-3 + (6x+0)/(x²+5)

(8x²-18x+10)/[(x^2+5)(x-3)] =

<h2>2/(x-3)+6x/x²+5</h2>

(4x+2)/[(x²+4)(x-2)]

(4x+2)/[(x²+4)(x-2)]= A/(x-2) + bx+c/(x²-2)

(4x+2)=a(x²-2)+(bx+c)(x-2)

follow the same step in the previous answer:

the answer is :

<h2>(4x+2)/[(x²+4)(x-2)]= 5/4/(x-2) + (3/2 -5x/4)/(x²+4)</h2>

8 0
2 years ago
Calculate the surface area of a triangular prism. It has an isosceles triangle face with a base of 4 m and a height of 3 m. The
son4ous [18]

Answer:

48 + 18√13 cm²

Step-by-step explanation:

HC = BC/2 = 4m/2 = 2 m

AC = √AH² + HC² = √9 + 4 = √13

A = 2×A(ABC) + 2×A(ACFD) + A(BCFE)

= 2×AH×BC/2 + 2×AC×CF + BC×CF

= 2×3×4/2 + 2×√13×9 + 4×9

=12 + 18√13 + 36

= 48 + 18√13 cm²

4 0
3 years ago
An image of a rectangular pyramid is shown below: A right rectangular pyramid is shown. Part A: A cross section of the rectangul
valentina_108 [34]

Answer:

Part a) Rectangle

Part b) Triangle

Step-by-step explanation:

<u><em>The picture of the question in the attached figure N 1</em></u>

Part A) A cross section of the rectangular pyramid is cut with a plane parallel to the base. What is the name of the shape created by the cross section?

we know that

When a geometric plane slices any right pyramid so that the cut is parallel to the plane of the base, the cross section will have the same shape (but not the same size) as the base, So, in the case of a right rectangular pyramid, the cross section is a rectangle

Part b)  If a cross section of the rectangular pyramid is cut perpendicular to the base, passing through the top vertex, what would be the shape of the resulting cross section?

we know that

Cross sections perpendicular to the base and through the vertex will be triangles

see  the attached figure N 2 to better understand the problem

5 0
3 years ago
What are the solutions to. x^2 - x - 20 = 0
nignag [31]

Step-by-step explanation:

<em>x² - x - 20 = 0</em>

<em>x²</em><em> </em><em>-</em><em> </em><em>(</em><em>5</em><em>-</em><em>4</em><em>)</em><em> </em><em>x </em><em>-</em><em> </em><em>2</em><em>0</em><em> </em><em>=</em><em> </em><em>0</em><em> </em>

<em>x²</em><em> </em><em>-</em><em> </em><em>5x </em><em>+</em><em> </em><em>4x </em><em>-</em><em>2</em><em>0</em><em> </em><em>=</em><em> </em><em>0</em>

<em>x </em><em>(</em><em> </em><em>x </em><em>-</em><em> </em><em>5</em><em>)</em><em> </em><em>+</em><em> </em><em>4</em><em> </em><em>(</em><em> </em><em>x </em><em>-</em><em> </em><em>5</em><em>)</em><em> </em><em>=</em><em> </em><em>0</em>

<em>(</em><em>x </em><em>-</em><em> </em><em>5</em><em>)</em><em> </em><em>(</em><em>x+</em><em> </em><em>4)</em><em> </em><em>=</em><em> </em><em>0</em>

<em>Either</em><em>. </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>

<em>x </em><em>-</em><em> </em><em>5</em><em> </em><em>=</em><em> </em><em>0</em>

<em>x </em><em>=</em><em> </em><em>5</em>

<em>Or, </em>

<em>x </em><em>+</em><em> </em><em>4</em><em> </em><em>=</em><em> </em><em>0</em><em> </em>

<em>x </em><em>=</em><em> </em><em>-</em><em>4</em>

3 0
3 years ago
Solve using the elimination method:<br> X-3y=7<br> 3x + 3y=9
sergij07 [2.7K]

Answer:

                        x=4\\\\y=-1

Step-by-step explanation:

Given Equation:

x-3y=7      Equation:1

3x + 3y=9     Equation:2

Dividing Equation:2 by '3' both the sides:

x+y=3      

or   x=3-y     Equation:3

Putting the vale of 'x' in Equation:1

                             x-3y=7

                          (3-y)-3y=7\\\\3-y-3y=7\\\\3-4y=7\\\\

Subtracting '3' both sides

                             -4y=7-3\\\\-4y=4

                                 y=\frac{4}{-4}

                                 y=-1

Putting value of 'y' in Equation:3

                                x=3-y

                                x=3-(-1)\\\\x=3+1\\\\x=4

The solution of the equations is :

                              x=4\\\\y=-1

7 0
3 years ago
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