Answer:
the answer is A. Y, X, Z, W
Explanation:
I took the test
Mass percentage of sodium chloride(NaCl) in ocean waters = 3.5 %
That means 3.5 g sodium chloride(NaCl) is present for every 100 g of ocean water.
The given mass of sodium chloride(NaCl) is 45.8 g
Calculating the mass of ocean waters that would contain 45.8 g sodium chloride(NaCl):
= 1309 g ocean water
Therefore, 45.8 g sodium chloride is present in 1309 g ocean water.
In pure water, all of the molecules in the liquid are water molecules so the mole fraction is 1 (100 % H2O, 55 mol/L). In sea water, the concentration of water molecules in the solution is less than that of pure water so the vapor pressure of sea water is also lower.
Answer:
84.24 g
Explanation:
Given data:
Mass of oxygen = 75 g
Mass of Al required to react = ?
Solution:
Chemical equation:
4Al + 3O₂ → 2Al₂O₃
Number of moles of oxygen:
Number of moles = mass/ molar mass
Number of moles = 75 g/ 32 g/mol
Number of moles = 2.34 mol
Now we will compare the moles of oxygen with Al.
O₂ : Al
3 : 4
2.34 : 4/3×2.34 = 3.12 mol
Mass of Al required:
Mass = number of moles × molar mass
Mass = 3.12 mol × 27 g/mol
Mass = 84.24 g
1) <u>Stereo-selective (or enantioselective)</u> reactions form predominately or exclusively one enantiomer.
2) Epoxidation is the addition of a single oxygen atom to an alkene to form an epoxide.
3) <u>Hydrogenation (or reduction)</u> of an alkene forms an alkane by addition of H₂.
4) <u>Dihydroxylation</u> is the addition of two hydroxy groups to a double forming, a 1,2-diol or glycol.
5) <u>oxidative</u> cleavage of an alkene breaks both the σ and π bonds of the double bond to form two carbonyl groups.
6) <u>Regioselective</u> reactions form predominately or exclusively one constitutional isomer.
7) <u>Syn</u> dihydroxylation results when an alkene is treated KMnO4 or OsO4, where each reagent adds two oxygen atoms to the same side of the double bond.
