____________________ solids break up into individual neutral particles when dissolved in a solvent.

Chemistry

2 answers:

Law Incorporation [45]3 years ago

7 0

D. molecular solids break up into...

love history [14]3 years ago

4 0

Answer:

d. molecular

Explanation:

A molecular solid is one that break up into individual neutral particle when dissolved in a solvent. Molecular solid are bonded by a weak van der wall forces when dissolved in a solvent these bonds break way and molecules end being neutral particles . hence option D is the correct answer

You might be interested in

Mushrooms have gills?

Mars2501 [29]

Mushrooms do have gills its those little pocket like things under the umbrella

7 0

3 years ago

Four modes of sediment transport are:

netineya [11]

Here is 5

Dissolved Load - elements dissolved in solution

Suspended Load - very fine grained sediment such as clay and silt carried in suspension. The size grains that can be carried in suspension are dependent on the current velocity

Wash Load - a subset of the suspension load, extremely small particles (clay) that will remain in suspension independent of turbulence in the river

Saltation Load - particles that are temporarily carried in suspension but move by bouncing along the bottom

Bed Load - sediment that moves by rolling or sliding along the bottom. These are generally the coarser grained sediments such as sand and gravel.

5 0

3 years ago

Use the ΔHrxn values of the following reactions: 2SO2(g) + O2(g) → 2SO3(g) ΔHrxn = –196 kJ 2S(s) + 3O2(g) → 2SO3(g) ΔHrxn = –790

sesenic [268]

Answer: The $\Delta H^o_{rxn}$ for the reaction is -297 kJ.

Explanation:

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

$S(s)+O_2(g)\rightarrow SO_2(g)$ $\Delta H^o_{rxn}=?$