Part a is 105 and part b is 180
Answer:
<h2>n < 43</h2>
Step-by-step explanation:
n + 19 < 62 <em>subtract 19 from both sides</em>
n + 19 - 19 < 62 - 19
n < 43
Both are D
First one:
f(g(x)) =f(x^2+3) then you x^2+3 is the x you are going to introduce in the function f
f(x^2+3)= sqrroot(x^2+3-3)= sqrroot (x^2) =x
Second:
you need to leave x alone
y = 3x^2 +1
y-1 = 3x^2
(y-1)/3 = x^2
sqrroot ((y-1)/3) = x
sqrroot ((x-1)/3) = h^-1(x)
If quantity t varies inversely with a quantity r ,
Then mathematically t α 1/r,
Introducing a constant, t = k/r .
When t = 6 then r = 5,
therefore, 6 = k/5
k = 6×5
k = 30 (Constant of variation)
Which means the equation connecting t and r will be t = 30/r
To find the value of t when r = 15, we use the equation of this variation
such that, t = 30/15
t = 2
I think it may be this one 40×9=360