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Gnom [1K]
2 years ago
15

A 47.35 g mass of copper is heated from 20 degrees celsius to 85 degrees celsius. How many joules were added to accomplish this?

Chemistry
1 answer:
lora16 [44]2 years ago
4 0

Answer:

1185.0 J.

Explanation:

  • The amount of heat needed to accomplish this process can be calculated using the formula:

<em>Q = m.C.ΔT</em>, where,

Q is the amount of heat needed,

m is the mass of the copper <em>(m = 47.35 g)</em>,

C is the specific heat of Cu<em> (C = 0.385 J/g.°C)</em>,

ΔT is the temperature difference (the final temperature - the initial temperature <em>(ΔT = 85.0 - 20.0 = 65.0 °C)</em>.

<em>∴ The amount of heat needed Q = m.C.ΔT </em>= (47.35 g) (0.385 J/g.°C) (65.0 °C) = 1184.933 J ≅ 1185.0 J.

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URGENTTTTT HELPPPP PLZZZ LAST TRYYY
algol13

Left Panel

A is an acid. Not the answer.

B is correct. That would be a base. But it is not an Arrhenius base. Keep reading.

C that is exactly what an Arrhenius base is.

D. No an acid of some sort would accept OH ions.

Right Panel

D is concentrated and it is also a weak base. Good cleaning fluid. Smells awful but it works.

8 0
2 years ago
Once formed, how are coordinate covalent bonds different from other covalent bonds?
-Dominant- [34]

Answer:

\boxed {\boxed {\sf {One \ atom \ donates \ both \ electrons \ in \ a \ pair}}}

Explanation:

A covalent bond involves the sharing of electrons to make the atoms more stable, and so they satisfy the Octet Rule (8 valence electrons).

Typically each atom contributes an electron to form an electron pair. This is a single bond. There are also double bonds (two pairs of electrons), triple bonds (three pairs of electrons), and coordinate covalent bonds.

Sometimes, to satisfy the Octet Rule and achieve stability, one atom contributes both of the electrons in an electron pair. This is different from other covalent bonds because usually each of the 2 atoms contributes an electron to make a pair.

4 0
3 years ago
8. How do you know when kinetic energy is not changing?
Nostrana [21]
Answer:

Kinetic energy is the energy of motion so to figure out that it’s not changing is if the object is still moving. If it’s staying still or is at rest, it is presenting potential energy, which is when energy is being stored inside the object.
5 0
2 years ago
Pls help! Polonium has a large, unstable nucleus. Through which process is it most likely to become stable?
Stella [2.4K]

The process through which Polonium is most likely to become stable is: B. alpha decay.

An unstable element refers to a chemical element that lose particles because its nucleus contain an excess of internal energy (neutron or proton).

This ultimately implies that, an unstable element is radioactive in nature.

In Science, some examples of an unstable element are:

  • Tritium.
  • Bismuth-209 .
  • Xenon.
  • Polonium.

Polonium is a chemical element with a large, unstable nucleus.

Basically, the most stable isotope of Polonium is Polonium-209, which typically undergoes an alpha decay to form lead-205 and the emission of an alpha particle.

⇒  ^{209}_{84}Po ----> ^{205}_{82}Pb \;+\; ^{4}_{2}\alpha

In conclusion, we can deduce from the above chemical equation that Polonium is most likely to become stable through an alpha decay.

Read more: brainly.com/question/18214726

5 0
2 years ago
Read 2 more answers
1. A gas having the following composition is burnt under a boiler with 50% excess air.
jeka94

The composition of the stack gas are :

CH_4= 0.8713

C_3H_8 = 0.0202

CO = 0.107

<h3 /><h3>What is a mole fraction?</h3>

The ratio of the number of moles of one component of a solution or other mixture to the total number of moles representing all of the components.

Assuming 100 g of the stack gas. Calculate the mass of each species in this sample according to their percentages.

Mass of CH_4 : 70% of 100 g = 70 g

Mass of C_3H_8 : 15% of 100 g = 15 g

Mass of CO : 15% of 100 g = 15 g

Now calculate the number of moles of each species:

Number of moles of CH_4 : \frac{70 g}{16.04 g/mol} = 4.3 mole

Number of moles of C_3H_8: \frac{15 g}{144.1 g/mol} = 0.10 mole

Mass of CO : \frac{15 g}{28.01 g/mol} = 0.53 mole

Now to calculate the mole fraction of each we use the formula:

Mole fraction of CH_4: \frac{4.3}{4.935} = 0.8713

Mole fraction of C_3H_8 : \frac{0.10}{4.935} = 0.0202

Mole fraction of CO : \frac{0.53}{4.935} = 0.107

Hence, composition of the stack gas are:

CH_4 = 0.8713

C_3H_8 = 0.0202

CO = 0.107

Learn more about mole fraction here:

brainly.com/question/13135950

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8 0
2 years ago
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