Answer:
1807.24L
Explanation:
Using combined gas law equation:
P1V1/T1 = P2V2/T2
Where;
P1 = pressure on Earth
P2 = Pressure on Mars
V1 = volume on Earth
V2 = volume on Mars
T1 = temperature on Earth
T2 = temperature on Mars
According to the information provided of the balloon in this question;
P1 = 1 atm
P2 = 4.55 torr = 4.55/760 = 0.00599atm
V1 = 14.5L
V2 = ?
T1 = 19°C = 19 + 273 = 292K
T2 = -55°C = -55 + 273 = 218K
Using P1V1/T1 = P2V2/T2
1 × 14.5/292 = 0.00599 × V2/218
14.5/292 = 0.00599V2/218
Cross multiply
14.5 × 218 = 292 × 0.00599V2
3161 = 1.74908V2
V2 = 3161 ÷ 1.74908
V2 = 1807.24L
Although the data is not stated, the standard enthalpy of formation of ammonia is -46 kJ/mol.
The standard enthalpy of formation of a substance is the change in enthalpy that occurs when one mole of that substance is produced from its elements in their standard states. The fact that the standard enthalpy of formation for ammonia is negative indicates that the formation of ammonia is an exothermic, or energy releasing, reaction.
Answer:
i.e belongs to same group because of valence electrons are same
Explanation:
so it has same chemical behaviour. and q has more energy than r ionisation energy decreases from top to bottom
Think it would be distillation
Yes this is true otherwise it would not be a solution
