In regards to this question, there are no options given to choose from and this makes the question difficult to answer. I hope the answer i am giving is the one you were looking for. The compound Mg(OH)2 when stirred in water will not pass through a filter paper as it is bound to form a sediment. This sediment will get stuck in the filter paper.
Dissolution means to make the compound apart, So when we have ionic compounds like NaI which has metal and non-metal ions, It separates into parts of positive ions and negative ions. After we separate this compound apart we will put the charge of each on above its symbol and then start to balance the equation of the dissolution.
So the dissolution equation of NaI is:
NaI(s) → Na^+(s) + I^-(Aqu)
Answer:
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Explanation:
The Percent composition of MgO is 60.304 % and 39.696 % respectively.
<h3>
What percentage of the given chemical is there?</h3>
Mg + 1/2O₂ -------> MgO
We now want to know the percent composition of MgO in light of this reaction. Since the original reactants' and the product's mass are not provided, we can use the component's atomic weights to solve this problem.
Let's compute the molar mass of MgO since Mg has a molecular weight of 24.305 g/mol and O has a molecular weight of 15.999 g/mol:
molar mass of 
Now with this weight, let's see the percent composition of this compound:
Mg percentage =
%
O percentage = 
%
The Percent composition of MgO is 60.304 % and 39.696 % respectively.
Learn more about percent composition here:-
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