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SIZIF [17.4K]
2 years ago
8

A sample of an unknown gas effuses in 11.1 min. An equal volume of H2 in the same apparatus at the same temperature and pressure

effuses in 2.42 min. What is the molar mass of the unknown gas
Chemistry
1 answer:
Anit [1.1K]2 years ago
7 0

Answer:

<em>Molar mass of the gas is 0.0961 g/mol</em>

<em></em>

Explanation:

The effusion rate of an unknown gas = 11.1 min

rate of H_{2} effusion = 2.42 min

molar mass of hydrogen = 1 x 2 = 2 g/m

molar mas of unknown gas = ?

From Graham's law of diffusion and effusion, the rate of effusion and diffusion is inversely proportional to the square root of its molar mass.

from

\frac{R_{g} }{R_{h} } = \sqrt{\frac{M_{h} }{M_{g} } }

where

R_{h} = rate of effusion of hydrogen gas

R_{g} = rate of effusion of unknown gas

M_{h} = molar mass of H2 gas

M_{g} = molar mass of unknown gas

substituting values, we have

\frac{11.1 }{2.42 } = \sqrt{\frac{2 }{M_{g} } }

4.587 = \sqrt{\frac{2 }{M_{g} } }

\sqrt{M_{g} } = \sqrt{2}/4.587

\sqrt{M_{g} } = 0.31

M_{g} = 0.31^{2} = <em>0.0961 g/mol</em>

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