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2 years ago

25.0 cm3 of a solution of sodium hydroxide required 18.8 cm3 of 0.0500 mol/dm3 H2SO4

Chemistry

1 answer:

marshall27 [118]2 years ago

7 0

Answer:

i think so

Ba(OH)2 + H2SO4 ------> BaSO4 + 2H2O

1) Moles of Ba(OH)2 = moles of H2SO4 = 0.025L x 2)0.02M = 5.0 x 10^-4M

Concn of Ba(OH)2 in g/L = 5.0 x 10^-4M x 171.33g/mol = 0.086g/mol

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Write a balanced nuclear equation for the following: The nuclide astatine-218 undergoes alpha emission to give bismuth-214

galina1969 [7]

Answer:

$^{218}_{85}At\rightarrow ^{214}_{83}Bi+^{4}_{2}He$

Explanation:

Hello there!

In this case, since the radioactive reaction for the alpha emission of astatine-218 to bismith-214 involve the release of a helium atom as shown below:

$^{218}_{85}At\rightarrow ^{214}_{83}Bi+^{4}_{2}He$

Whereas the atomic number decreases by 2 and the mass number by 4 in agreement to the release of the Helium atom.

Regards!

7 0

2 years ago

ELECTROLYSIS OF MOLTEN NaCl IS DONE IN A DOWNS CELL OPERATING AT 7.0 VOLTS AND 4.0X10^4A. HOW MUCH Na(s) AND Cl2(g) CAN BE PRODU

Greeley [361]

Answer:

Mass of sodium produced = 2.74 × 10⁵ g of Na

Mass of chlorine produce = 4.24 × 10⁵ g of Cl₂

Explanation:

In the electrolysis of molten NaCl as described above, the quantity of charge used is given by the formula, Q = I × t

Where I isnthe current passed in amperes and t is time in seconds.

Q = 4.0 × 10⁴ A × (8 × 60 × 60) s = 1.152 × 10⁹ C

Equation for the discharge of sodium is; Na+ + e- ---> Na (s)

One mole of electrons is required to discharge one mole of Na

One mole of electron = 1 faraday = 96500 C

One mole of Na has a mass of 23 g

96500 C produces 23 g of Na

1.152 × 10⁹ C will produce 23 g × 1.152 × 10⁹ C / 96500 C = 2.74 × 10⁵ g of Na

Equation for the discharge of chlorine gas is; 2 Cl- ---> Cl₂(g) + 2e-

Two mole of electrons are required to discharge one mole of chlorine gas

Two moles of electron = 2 faraday = 2 × 96500 C = 193000

One mole of Cl₂ has a mass of 71 g

193000 C produces 71 g of Cl₂

1.152 × 10⁹ C will produce 71 g × 1.152 × 10⁹ C / 193000 C = 4.24 × 10⁵ g of Cl₂

5 0

2 years ago

I need the answers any help can be good

aleksandrvk [35]

2.a)R b)R c)L d)L e)R f)L g)L

8 0

2 years ago

(Numerical problems) A car is running with the velocity of 72km/h. What will be it's velocity after 5s if it's acceleration is -

kodGreya [7K]

The car's velocity after 5s : 10 m/s

<h3>Further explanation</h3>

Given

velocity=v=72 km/h=20 m/s

time=t = 5 s

acceleration=a = -2 m/s²

Required

velocity after 5s

Solution

Straight motion changes with constant acceleration

$\tt v_f=v_i+at$

vf=final velocity

vi = initial velocity

Input the value :

$\tt v_f=20+(-2).5\\\\v_f=20-10\\\\v_f=10~m/s$

The car is decelerating (acceleration is negative) so that its speed decreases

4 0

2 years ago

Hecking skills activated

artcher [175]

Answer:

yes 34

Explanation:

4/13 =0.307

7 0

2 years ago

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