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Vinil7 [7]
3 years ago
14

For the equilibrium reaction 2NH3(g) + 22 kJ ↔ N2(g) + 3H2(g), which of the following changes would result in the formation of m

ore N2 and H2 at equilibrium?
Chemistry
1 answer:
daser333 [38]3 years ago
3 0
Hello! Your question seems incomplete, still I will try to answer it in a general way. As shown in in equation 22 KJ heat is absorbed during the reaction so it is endothermic reaction.

Effect of Temperature:
According to Le Chatelier's principle, by increasing temperature the equilibrium will shift in the forward direction hence more nitrogen and hydrogen will produce.

Effect of Pressure:
It is evident from the reaction that there is an increase in volume in the formation of N2 and H2 (4 moles in whole), Hence, decrease in pressure on this system in equilibrium state will adjust itself in a direction in which the volume is increased i.e. formation of N2 and H2.

Effect of Concentration:
Increasing concentration of NH3, removal of N2 or removal of H2 will shift the equilibrium in forward direction, Hence more product is formed.
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Bauxite must go through two processes to produce aluminum metal. The yield of the Bayer process, which extracts aluminum oxide f
Mashcka [7]

The yield of aluminium obtained from 1 m^3 of bauxite is 419810 g

<h3>What is a Percent yield</h3>

A percent yield of a substance measures the amount of the substance actually obtained as a percentage ratio of expected yield.

Percent yield = actual yield / expected yield × 100%

<h3>How to calculate the mass of aluminium obtained from bauxite </h3>

From the data given:

40 % of the bauxite is converted to aluminium oxide.

Volume of bauxite = 1 m^3

40 % of 1 m^3 = 0.4 m^3

volume of aluminium oxide = 0.4 m^3

density of aluminium oxide = 3965 kg/m^3

  • Using mass = density × volume

mass of aluminium oxide = 0.4 × 3965 kg

mass of aluminium oxide = 1586 kg

Formula of aluminium oxide is Al203

molar mass of aluminium oxide = 102 g

  • percentage mass of aluminium in one mole of aluminium oxide = mass of aluminium / mass of aluminium oxide × 100 %

Percentage mass of aluminium in aluminium oxide = 54/102 × 100

Percentage mass of aluminium in aluminium oxide = 52.94 %

Expected mass of aluminium from aluminium oxide = 52.94 × 1586

Expected mass of aluminium = 839.62 kg

Actual yield = 40 % × 839.62

Actual yield of aluminium = 419.81 kg

mass of aluminium in grams = 419810 g

Therefore, mass of aluminium obtained from 1 m^3 of bauxite is 419810 g

Learn more about percent yield at: brainly.com/question/8638404

3 0
2 years ago
The Gateway Arch in St. Louis, MO is approximately 630 ft tall. How many U.S. dimes would be in a stack of the same
miskamm [114]

Answer:

142240

Explanation:

We are told in the question:

Height of Gateway Arch in St. Louis, MO = 630ft

We are asked, how many U.S. dimes would be in a stack of the same

height when 1 dime is 1.35 mm thick.

Step 1

Convert height in ft to mm

1 ft = 304.8 mm

630ft =

Cross Multiply

630ft × 304.8mm/1ft

= 192024 mm.

Step 2

To find how many US dimes would be in a stack of the same height

= Total thickness/ Thickness of 1 US dime

= 192024 mm/1.35mm

= 142240

Therefore, the number of dimes that would be in a stack of the same

height is 142240

6 0
3 years ago
Mg + 2HCl ⟶ MgCl2 + H2
Ivanshal [37]

Answer: m = 24.31 g/mol · 1.13 mol

Explanation: 2 mol HCl use 1 mol Mg.

Magnesium is used 0.5 · 2.26 mol = 1.13 mol

M(Mg) = 24.31 g/ mol

7 0
3 years ago
What is the volume of 88 grams of CO2 gas at STP?
I am Lyosha [343]
! mole of CO2 at STP has a volume of 22.4 liters
88 grams = 2 moles 

so the required volume = 2*22.4 = 44.8 liters
3 0
3 years ago
What kind of non-flowering plant produces seeds instead of spores?
Pie

Answer:

The answer to your question is Ferns

Explanation:

Ferns are called nonflowering plants and produce spores instead of seeds.

6 0
3 years ago
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