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Vinil7 [7]
3 years ago
14

For the equilibrium reaction 2NH3(g) + 22 kJ ↔ N2(g) + 3H2(g), which of the following changes would result in the formation of m

ore N2 and H2 at equilibrium?
Chemistry
1 answer:
daser333 [38]3 years ago
3 0
Hello! Your question seems incomplete, still I will try to answer it in a general way. As shown in in equation 22 KJ heat is absorbed during the reaction so it is endothermic reaction.

Effect of Temperature:
According to Le Chatelier's principle, by increasing temperature the equilibrium will shift in the forward direction hence more nitrogen and hydrogen will produce.

Effect of Pressure:
It is evident from the reaction that there is an increase in volume in the formation of N2 and H2 (4 moles in whole), Hence, decrease in pressure on this system in equilibrium state will adjust itself in a direction in which the volume is increased i.e. formation of N2 and H2.

Effect of Concentration:
Increasing concentration of NH3, removal of N2 or removal of H2 will shift the equilibrium in forward direction, Hence more product is formed.
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pantera1 [17]

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6 0
3 years ago
Read 2 more answers
As temperature increases, the amount of solute that a solvent can dissolve increases. True False
ra1l [238]

<span>As temperature increases, the amount of solute that a solvent can dissolve increases.</span>



<span>Answer: False
</span>

6 0
3 years ago
A sample of food containing 27 g of fat, 48 g of carbohydrates and 20 g of protein is burned in a bomb calorimeter. In a perfect
rosijanka [135]

Answer:

38.3958 °C  

Explanation:

As,

1 gram of carbohydrates on burning gives 4 kilocalories  of energy

1 gram of protein on burning gives 4 kilocalories  of energy

1 gram of fat on burning gives 9 kilocalories of energy

Thus,

27 g of fat on burning gives 9*27 = 243 kilocalories of energy

20 g of protein on burning gives 4*20 = 80 kilocalories  of energy

48 gram of carbohydrates on burning gives 4*48 = 192 kilocalories  of energy

Total energy = 515 kilocalories

Using,

Q=m_{water}\times C_{water}\times (T_f-T_i)

Given: Volume of water = 23 L = 23×10⁻³ m³

Density=\frac{Mass}{Volume}  

Density of water= 1000 kg/m³

So, mass of the water:  

Mass\ of\ water=Density \times {Volume\ of\ water}  

Mass\ of\ water=1000 kg/m^3 \times {0.023\ m^3}  

Mass of water  = 23 kg

Initial temperature = 16°C  

Specific heat of water = 0.9998 kcal/kg°C  

515=23\times 0.9998\times (T_f-16)

Solving for final temperature as:

<u>Final temperature = 38.3958 °C  </u>

8 0
3 years ago
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Alex777 [14]
The Golgi, that’s the answer:)
7 0
3 years ago
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Be sure to answer all parts. Rubidium and bromine atoms are depicted at right. Answer the following questions. (a) What is the c
finlep [7]

The complete question is found on the image attached.

Answer:

a) Rb= +1, Br= -1

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Explanation:

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This RbBr is an ionic compound.

6 0
3 years ago
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