Which choices are equivalent to the expression below? check all that apply (image provided)

Mathematics

1 answer:

Marrrta [24]1 year ago

8 0

Answer:

D, E, and A

Step-by-step explanation:

Because 4 is also equivelent to square root of 16 and square root of 16 times square root of 3 is equal to square root of 48 which is D, and E is also correct because square root 24 x square root 2 is also square root 48 and same concept with A.

You might be interested in

PLZ help with 6th math homework!

vitfil [10]

I'm not doing your math homework, this is to help you learn and pass your test :) I will however show you a trick. ask your self this... "What can i factor out of 4x that i can also factor out of 8, which this would be 4. Now what you do if you divide everything by 4

4x/4 = x
8/4 = 2

so 4(x+2) is 4x+8 fully factored, NOW to check, use the distributive property, Multiply 4 back into x+2
4*x = 4x
4*2 = 8
so 4(x+2) = 4x+8

3 0

2 years ago

All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be

Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a student is proficient in reading but not mathematics and $A \cap B$ is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

$B = b + (A \cap B)$

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

$(A \cup B) + C = 1$