Answer:
t= 4.5 mm
Explanation:
Given that
P = 520 KPa ( gauge)
Maximum allowable normal stress ,σ= 150
d= 2.6 m
Wall thickness = t
The normal stress for pressure vessel given as
( hoop stress)
We always take maximum stress for safe design.

Now by putting the values

t= 4.5 mm
So the minimum thickness, t, of the wall is 4.5 mm
Answer:
a) 22.5number
b) 22.22 m length
Explanation:
Given data:
Bridge length = 500 m
width of bridge = 12 m
Maximum temperature = 40 degree C
minimum temperature = - 35 degree C
Maximum expansion can be determined as

where , \alpha is expansion coefficient
degree C
SO, 

number of minimum expansion joints is calculated as

b) length of each bridge

These parts are commonly called carburetor emulsion tubes. These tubes maintain the air-fuel ratio at different speeds.
The carburetor is a device of the combustion engine power supply system that mixes fuel and air in order to facilitate internal combustion.
The carburetor emulsion tubes are tubes that maintain the air-fuel ratio at different velocities.
These tubes (carburetor emulsion tubes) are small brass cylinders where the metering needle slides into them.
Learn more about carburetors here:
brainly.com/question/4237015
Answer:
The shear strain is 0.05797 rad.
Explanation:
Shear strain is the ratio of change in dimension along the shearing load direction to the height of the plate under application of shear load. Width of the plate remains same. Length of the plate slides under shear load.
Step1
Given:
Height of the pad is 1.38 in.
Deformation at the top of the pad is 0.08 in.
Calculation:
Step2
Shear strain is calculated as follows:



For small angle of
,
can take as
.

Thus, the shear strain is 0.05797 rad.