Answer:
Is this chemistry or ELA!
The downward slope represents the relation between durability of titanium and temperature because with increase temperature, strength of titanium decreases.
<h3>Can titanium withstand temperatures?</h3>
Titanium alloys have high tensile strength to weight ratio, good toughness and an ability to bear extreme temperatures of more than 600 °Celsius. This shows that if temperature increase from more than 600 °Celsius, the strength of the titanium tends to decrease because it can not withstand to it so the graph comes to downward when the temperature exceeds to 600°C.
So we can conclude that the downward slope represents the relation between durability of titanium and temperature because with increase temperature, strength of titanium decreases.
Learn more about temperature here: brainly.com/question/4735135
#SPJ1
Answer:
12.8 g of
must be withdrawn from tank
Explanation:
Let's assume
gas inside tank behaves ideally.
According to ideal gas equation- 
where P is pressure of
, V is volume of
, n is number of moles of
, R is gas constant and T is temperature in kelvin scale.
We can also write, 
Here V, T and R are constants.
So,
ratio will also be constant before and after removal of
from tank
Hence, 
Here,
and 
So, 
So, moles of
must be withdrawn = (0.66 - 0.26) mol = 0.40 mol
Molar mass of
= 32 g/mol
So, mass of
must be withdrawn = 
<span>aluminium phosphide AlP</span>