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3 years ago

The wave like behavior of moving particles cannot be observed due to the.........of the particles wavelengths?

Chemistry

2 answers:

jasenka [17]3 years ago

8 0

Answer: 4) mass

Explanation:

heplfull you btanliest me bro

Nat2105 [25]3 years ago

7 0

Answer is: 4)Mass

I really hope this helped you out!!!!

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Are atoms the smallest particles we know about, or are there smaller ones?

Schach [20]

Answer:

That we know about yes, but physicians still say there are more things out there. (we do not know about these yet tho)

Explanation:

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3 years ago

What do nonmetals and metals seek to do when having full outermost shells?

IceJOKER [234]

Answer: C

Explanation:

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2 years ago

A sample of a compound of xenon and fluorine contains molecules of a single type; XeFn, where n is a whole number. If 5.0 x 1020

kicyunya [14]

Answer:

Explanation:

Avogadro’s number represent the number of the constituent particles which are present in one mole of the substance. It is named after scientist Amedeo Avogadro and is denoted by $N_0$ .

Also, it is the number of particles in exactly 12.000 g of isotope carbon 12.

Avogadro constant:-

$N_a=6.023\times 10^{23}$

Hence,

Mass of $XeF_n$ = 131.293+ n18.998 g

So,

$6.023\times 10^{23}$ molecules have a mass of 131.293+ n18.998 g

Also,

$1$ molecules have a mass of $\frac{(131.293+ n18.998)}{6.023\times 10^{23}}$ g

So,

$5.0\times 10^{20}$ molecules have a mass of $\frac{(131.293+ n18.998)}{6.023\times 10^{23}}\times 5.0\times 10^{20}$ g

Also, given mass = 0.172 g

Thus,

$\frac{(131.293+ n18.998)}{6.023\times 10^{23}}\times 5.0\times 10^{20}=0.172$

$\frac{18.998n+131.293}{1204.6}=0.172$

$18.998n+131.293=207.1912$

$n=\frac{75.8982}{18.998}=4$

<u>Thus, value of n is 4.</u>

4 0

2 years ago

Calculate the standard free-energy change at 25 ∘C for the following reaction:

lianna [129]

Answer:

Standard free-energy change at $25^{0}\textrm{C}$ is $-3.80\times 10^{2}kJ/mol$

Explanation:

Oxidation: $Mg(s)-2e^{-}\rightarrow Mg^{2+}(aq.)$

Reduction: $Fe^{2+}(aq.)+2e^{-}\rightarrow Fe(s)$

--------------------------------------------------------------------------------------

Overall: $Mg(s)+Fe^{2+}(aq.)\rightarrow Mg^{2+}(aq.)+Fe(s)$

Standard cell potential, $E_{cell}^{0}=E_{Fe^{2+}\mid Fe}^{0}-E_{Mg^{2+}\mid Mg}^{0}$

So, $E_{cell}^{0}=(-0.41V)-(-2.38V)=1.97V$

We know, standard free energy change at $25^{0}\textrm{C}$ ( $\Delta G^{0}$ ): $\Delta G^{0}=-nFE_{cell}^{0}$

where, n is number of electron exchanged during cell reaction, 1F equal to 96500 C/mol

Here n = 2

So, $\Delta G^{0}=-(2)\times (96500C/mol)\times (1.97V)=-380210J/mol=-380.21kJ/mol=-3.80\times 10^{2}kJ/mol$

8 0

3 years ago

Read 2 more answers

What is the mass, in grams, of 9.01 x 1024 molecules of methanol (CH, OH) ?

Zina [86]

Answer:

480.6 g

Explanation:

Given data:

Number of molecules of methanol = 9.01 ×10²⁴

Mass in gram = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ molecules

9.01 ×10²⁴molecules ×1 mol /6.022 × 10²³ molecules

1.5 ×10¹ mol

15 mol

Mass in gram:

Mass = number of moles × molar mass

Mass = 15 mol × 32.04 g/mol

Mass = 480.6 g

3 0

3 years ago