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ollegr [7]
3 years ago
8

Which sample of water contains particles having the highest average kinetic energy ?

Chemistry
1 answer:
creativ13 [48]3 years ago
3 0
25mL if water as the highest average of the kinetic energy
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Air, with an initial absolute humidity of 0.016 kg water per kg dry air, is to be dehumidified for a drying process by an air co
amid [387]

Answer:

(a) The proportion of dry air bypassing the unit is 14.3%.

(b) The mass of water removed is 1.2 kg per 100 kg of dry air.

Explanation:

We can express the proportion of air that goes trough the air conditioning unit as p_{d} and the proportion of air that is by-passed as p_{bp}, being p_{d}+p_{bp}=1.

The amount of water that goes into the drier inlet has to be 0.004 kg/kg, and can be expressed as:

0.004 = 0.016*p_{bp}+ 0.002*p_{d}

Replacing the first equation in the second one we have

0.004 = 0.016*(1-p_{d})+ 0.002*p_{d}=0.016-0.016*p_{d}+0.002*p_{d}\\0.004 - 0.016 = (-0.016+0.002)*p_{d}\\-0.012 = -0.014*p_{d}\\p_{d}=\frac{-0.012}{-0.014}=0.857\\\\p_{bp}=1-p_{d}=1-0.857=0.143

(b) Of every kg of dry air feed, 85.7% goes in to the air conditioning unit.

It takes (0.016-0.002)=0.014 kg water per kg dry air feeded.

The water removed of every 100 kg of dry air is

100 kgDA*0.857*0.014 kgW/kgDA= 1.1998 \approx 1.2 kgW

It can also be calculated as the difference in humiditiy between the inlet and the outlet: (0.016-0.004=0.012 kgW/kDA) and multypling by the total amount of feed (100 kgDA).

100 * 0.012 = 1.2 kgW

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3 years ago
Calculate the molecular weight of freon-12, if 122.70 liters of its vapor at 200.00
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PV = nRT

Where:


P = pressure in atm = 700/760 = 0.9211atm


V = volume = 8.29L


R = gas constant, 0.08206 atm-L/mol-K


T = temperature in Kelvin = 200 + 273 = 473


n = numbers of moles  = Mass/molar mass


mass of the compound = 30.5


we can rewrite the equation above as


PV = (Mass)/(Molar mass) * RT







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