How does light behaves when light passes through water?
1 answer:
light bends towards the normal when passing from air to water.
Explanation:
when Light passes from air to water It gets refracted and bend towards normal and if it passes from water to air it bends away from normal. This is because of the difference in density of the medium. Light when passing through higher density to lower bends away from normal and on passing through lower density to higher bends towards normal.
in general, some of the rays of light will reflect from the surface of water but other will pass through the water. The normal is the perpendicular line drawn on the surface at the exact point of incident.
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Answer:
Explanation:
This is a recoil problem, which is just another application of the Law of Momentum Conservation. The equation for us is:
which, in words, is
The momentum of the astronaut plus the momentum of the piece of equipment before the equipment is thrown has to be equal to the momentum of all that same stuff after the equipment is thrown. Filling in:
Obviously, on the left side of the equation, nothing is moving so the whole left side equals 0. Doing the math on the right and paying specific attention to the sig fig's here (notice, I added a 0 after the 4 in the velocity value so our sig fig's are 2 instead of just 1. 1 is useless in most applications).
0 = 90.0v - 2.0 and
2.0 = 90.0v so
v = .022 m/s This is the rate at which he is moving TOWARDS the ship (negative was moving away from the ship, as indicated by the - in the problem). Now we can use the d = rt equation to find out how long this process will take him if he wants to reach his ship before he dies.
12 = .022t and
t = 550 seconds, which is the same thing as 9.2 minutes