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finlep [7]
2 years ago
5

How does light behaves when light passes through water?

Physics
1 answer:
MrMuchimi2 years ago
7 0

light bends towards the normal when passing from air to water.

Explanation:

when Light passes from air to water It gets refracted and bend towards normal and if it passes from water to air it bends away from normal. This is because of the difference in density of the medium. Light when passing through higher density to lower bends away from normal and on passing through lower density to higher bends towards normal.

in general, some of the rays of light will reflect from the surface of water but other will pass through the water. The normal is the perpendicular line drawn on the surface at the exact point of incident.

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When a candle is burning the candle is releasing thermal and radiant energy
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What is a hypothesis
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A hypothesis can be described as an intelligent guess 
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A hot-water bottle contains 787 g of water at 75∘C. If the liquid water cools to body temperature (37 ∘C), how many kilojoules o
IgorC [24]

Answer:

Q = 787 gr * 1 \frac{cal}{gr C} *(37-75)C = -29906 cal

So then the answer for this case would be 29906 cal but we need to convert this into KJ and we know that 1 cal = 4.184 J and if we convert we got:

29906 cal *\frac{4.184 J}{1 cal}* \frac{1KJ}{1000 J}= 125.127 KJ

Explanation:

For this case we know the mass of the water given :

m = 787 gr

And we know that the initial temperature for this water is T_i =75 C.

We want to cool this water to the human body temperature T_f = 37 C

Since the temperatures given are not near to 0C (fusion point) or 100C (the boling point) we don't need to use latent heat, then the only heat involved for this case is the sensible heat given by:

Q= m c_p \Delta T

Where c_p represent the specific heat for the water and this value from tables we know that c_p =1 \frac{cal}{gr C} for the water.

So then we have everything in order to replace into the formula of sensible heat and we got:

Q = 787 gr * 1 \frac{cal}{gr C} *(37-75)C = -29906 cal

So then the answer for this case would be 29906 cal but we need to convert this into KJ and we know that 1 cal = 4.184 J and if we convert we got:

29906 cal *\frac{4.184 J}{1 cal}* \frac{1KJ}{1000 J}= 125.127 KJ

8 0
3 years ago
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A cruise ship sails due south at 2.00 m/s while a coast guard patrol boat heads 19.0° north of east at 5.60 m/s. What are the x-
Lilit [14]

Answer:

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Explanation:

Given that,

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v_{b_{x}}=v_{b}\cos\theta

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7 0
3 years ago
HELP!!!
Vitek1552 [10]
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