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umka2103 [35]
3 years ago
12

Trying out for the big leagues, you throw a 149 gram baseball at a speed of 85.0 miles per hour. What is the ball's kinetic ener

gy (j) ?
Physics
1 answer:
nika2105 [10]3 years ago
3 0

Answer:

K.E=107.56J

Explanation:

Given data

v=85 miles/hour

convert it to meter per second we get

v=37.9984 meter/second

m (baseball mass)=149 gram

convert it to Kg we get

m=0.149 kg

K.E (Kinetic Energy)=?

Solution

K.E=\frac{1}{2}mv^{2}\\  K.E=\frac{1}{2} *(0.149)* (37.9984)^{2}\\ K.E=107.56J

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A Thomson's gazelle can run at very high speeds, but its acceleration is relatively modest. A reasonable model for the sprint of
NikAS [45]

Answer:

The gazelles top speed is 27.3 m/s.

Explanation:

Given that,

Acceleration = 4.2 m/s²

Time = 6.5 s

Suppose we need to find the gazelles top speed

The speed is equal to the product of acceleration and time.

We need to calculate the gazelles top speed

Using formula of speed

v=at

Where, v = speed

a = acceleration

t = time

Put the value into the formula

v=4.2\times6.5

v=27.3\ m/s

Hence, The gazelles top speed is 27.3 m/s.

6 0
3 years ago
Which of the following statements must be true?
anyanavicka [17]

Answer:

your answer is B. The velocity could be in any direction, but the acceleration is in the direction of the resultant force

6 0
3 years ago
What is the period of a wave if 3 waves passes every 6 seconds
Naya [18.7K]
Time period = time/no. of waves = 6/3 = 2s
4 0
3 years ago
Provide the following information for each of the three types of radiations from naturally radioactive materials. Be sure to inc
scoundrel [369]

<em>Alpha radiation:</em>  Particles.  Each alpha particle is a little bundle of 2 protons and 2 neutrons ... identical to the nucleus of a Helium atom.

Charge  . . . +2 elementary charges

Mass  . . . 4 Atomic Mass Units

Relative penetrating power  . . . low

The effect an electric field would have on it . . . Since the alpha particle has a positive charge, it's repelled by other positive charges, and attracted toward negative charges.

<em>Beta radiation</em>:  Particles.  Each beta particle is an electron.

Charge  . . . -1 elementary charge

Mass  . . . 0.00055 AMU

Relative penetrating power  . . . medium

The effect an electric field would have on it . . .  repelled by other negative charges, and attracted toward positive charges.

<em>Gamma radiation</em>:  electromagnetic wave, verrrrry short wave, high frequency

Charge . . . electromagnetic wave, no charge

Mass  . . . electromagnetic wave, no mass

Relative penetrating power  . . . high

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5 0
3 years ago
The parallel plates in a capacitor, with a plate area of 8.00 cm2 and an air-filled separation of 2.70 mm, are charged by a 8.70
MrRa [10]

Answer:

a)  ΔV₁ = 21.9 V, b) U₀ = 99.2 10⁻¹² J, c) U_f = 249.9 10⁻¹² J,  d)  W = 150 10⁻¹² J

Explanation:

Let's find the capacitance of the capacitor

         C = \epsilon_o \frac{A}{d}

         C = 8.85 10⁻¹² (8.00 10⁻⁴) /2.70 10⁻³

         C = 2.62 10⁻¹² F

for the initial data let's look for the accumulated charge on the plates

          C = \frac{Q}{\Delta V}

          Q₀ = C ΔV

           Q₀ = 2.62 10⁻¹² 8.70

           Q₀ = 22.8 10⁻¹² C

a) we look for the capacity for the new distance

          C₁ = 8.85 10⁻¹² (8.00 10⁻⁴) /6⁴.80 10⁻³

          C₁ = 1.04 10⁻¹² F

       

          C₁ = Q₀ / ΔV₁

          ΔV₁ = Q₀ / C₁

          ΔV₁ = 22.8 10⁻¹² /1.04 10⁻¹²

          ΔV₁ = 21.9 V

b) initial stored energy

          U₀ = \frac{Q_o}{ 2C}

          U₀ = (22.8 10⁻¹²)²/(2  2.62 10⁻¹²)

          U₀ = 99.2 10⁻¹² J

c) final stored energy

          U_f = (22.8 10⁻¹²) ² /(2  1.04 10⁻⁻¹²)

          U_f = 249.9 10⁻¹² J

d) the work of separating the plates

as energy is conserved work must be equal to energy change

          W = U_f - U₀

          W = (249.2 - 99.2) 10⁻¹²

          W = 150 10⁻¹² J

note that as the energy increases the work must be supplied to the system

6 0
3 years ago
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