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skelet666 [1.2K]
2 years ago
6

Assuming you exert a constant force on the wagon, how fast is it moving after 5 seconds?

Physics
1 answer:
Gelneren [198K]2 years ago
3 0
I would help but I’m also taking this
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I need help doing this i don’t understand what to do
Hatshy [7]

Answer:

You need to write an essay with 800 to 1,200 words. That talks about the significance of one of the seminal works (Definition- a work that strongly influenced people. Example: Martin Luther King Jr's speech "I Have A Dream") in the unit and how it connects to current issues (Example- Politics). It should be clearly stated and should be well supported by research (Example- a trustworthy article talking about its influence). You should properly cite at least 3 good sources from different perspectives. (Example- a republicans view for one source, a democratic for another, and a neutral for the third) You should also use direct quotes (Example: "Let them eat cake." - Marie Antoinette) and paraphrase- put it in your own words. (Example: Marie Antoinette said that they should eat cake.) I hope this helps, good luck! :)

Explanation:

7 0
2 years ago
Take the mechanical equivalent of heat as 4 J/cal. A 10-g bullet moving at 2000 m/s plunges
klasskru [66]

Assuming that all the bullet’s energy heats the paraffin, its final temperature is 27.1 degree C. The correct option is D.

<h3>What is temperature?</h3>

Temperature is the degree of hotness and coldness of the material.

The energy of the bullet E = 1/2 mv²

E = 1/2 x 10 x 10⁻³ x (2000)²

E = 2 x 10⁴ J

This heat is used in heating the paraffin

E = m x c ΔT = m x c (Tfinal -Tinitial)

2 x 10⁴ J = 1 x 2.8 x 10³ x (Tfinal -20)

Tfinal = 27.1°C

Thus, the final temperature is 27.1 degree C. The correct option is D.

Learn more about temperature.

brainly.com/question/15267055

#SPJ1

4 0
2 years ago
An astronaut on the moon drops a feather from rest (v = 0). The acceleration due to gravity is 1.67 m/s​ 2​ . If the feather beg
olga_2 [115]

Given :

Initial velocity , u = 0 m/s .

Acceleration due to gravity on moon , g_m=1.67\ m/s^2 .

Height , h = 2 m .

To Find :

Final position after falling for 1.5 seconds .

Solution :

We know , by equation of motion :

s=ut+\dfrac{at^2}{2}

Here , a = g_m .

So , equation will transform by :

s=ut+\dfrac{g_mt^2}{2}\\\\s=0+\dfrac{1.67\times 1.5^2}{2}\ m\\\\s=1.88\ m

Therefore , the height form moon's surface is 1.88 m .

Hence , this is the required solution .

6 0
3 years ago
What can you caculate if you know the frequency and speed of a wave
Mila [183]

Frequency and speed = wavelength.

4 0
3 years ago
) Force F = − + ( 8.00 N i 6.00 N j ) ( ) acts on a particle with position vector r = + (3.00 m i 4.00 m j ) ( ) . What are (a)
natali 33 [55]

To develop this problem it is necessary to apply the concepts related to the Cross Product of two vectors as well as to obtain the angle through the magnitude of the angles.

The vector product between the Force and the radius allows us to obtain the torque, in this way,

\tau = \vec{F} \times \vec{r}

\tau = (8i+6j)\times(-3i+4j)

\tau = (8*4)(i\times j)+(6*-3)(j\times i)

\tau = 32k +18k

\tau = 50 k

Therefore the torque on the particle about the origen is 50k

PART B) To find the angle between two vectors we apply the definition of the dot product based on the vector quantities, that is,

cos\theta = \frac{r\cdot F}{|\vec{r}|*|\vec{F}|}

cos\theta = \frac{(8*-3)+(4*3)}{\sqrt{(-3)^2+4^2}*\sqrt{8^2+6^2}}

cos\theta = -0.24

\theta = cos^{-1} (-0.24)

\theta = 103.88\°

Therefore the angle between the ratio and the force is 103.88°

5 0
2 years ago
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