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DedPeter [7]
3 years ago
7

Which expression represents the distance between −14.6 and −5.2 on the number line? 

Mathematics
2 answers:
algol133 years ago
7 0

Answer:

9.4

Step-by-step explanation:

nadezda [96]3 years ago
5 0
9.4 should be the answer
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Triangle BCD is isosceles and line Bc is congruent to line BD. What is the measure of arc BC?
Leokris [45]
Since arc CD is 100 degrees, the rest of the circle must be 260 degrees.  Since the rest of the circle is made up of two equal arcs, then arc BC must be half of 260 degrees.  Thus, the answer is 130 degrees, C.
7 0
4 years ago
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40pts!! Select the correct answer. <br> Simplify.
stiv31 [10]

Hey!

-------------------------------------------------

Solution:

=\frac{3x^2y^3}{z^3}

Cube the coefficients.

= \frac{27x^2y^3}{z^3}

Multiply the exponents.

= \frac{27x^6y^9}{z^9}

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Answer:

Option D.

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Hope This Helped! Good Luck!

5 0
3 years ago
Perform the indicated operation and write in standard form 5i+(-9-i)
antoniya [11.8K]
Since the sign before the parentheses is a + , we can just remove the parentheses.

<span>5i + (-9 - i) = 5i - 9 - i = -<u>9 + 4i</u></span>


3 0
3 years ago
Read 2 more answers
Simplify . (1/c + 1/h)/(1/(c ^ 2) - 1/(r ^ 2))
Marrrta [24]

Answer:

\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}

Step-by-step explanation:

\frac{\frac{1}{c}+\frac{1}{h}}{\frac{1}{c^2}-\frac{1}{r^2}}

Combine \frac{1}{c} + \frac{1}{h}

\frac{\frac{h+c}{ch}}{\frac{1}{c^2}-\frac{1}{r^2}}

Combine the bottom, too.

=\frac{\frac{h+c}{ch}}{\frac{r^2-c^2}{c^2r^2}}

Apply the fraction rule

=\frac{\left(h+c\right)c^2r^2}{ch\left(r^2-c^2\right)}

Cancel

=\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}

Therefore, \frac{\left(\frac{1}{c}+\frac{1}{h}\right)}{\left(\frac{1}{\left(c^2\right)}-\frac{1}{\left(r^2\right)}\right)}:\quad \frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}

5 0
3 years ago
2x+3y= 14<br>3х - 4 y = 4<br><br>​
goldenfox [79]

The solution to given system of equations are (x, y) = (4, 2)

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

2x + 3y = 14 ---------- eqn 1

3x - 4y = 4 --------- eqn 2

We have to solve the given system of equations

We can solve the above system of equations by elimination method

<em><u>Multiply eqn 1 by 3</u></em>

3(2x + 3y = 14)

6x + 9y = 42 --------- eqn 3

<em><u>Multiply eqn 2 by 2</u></em>

2(3x - 4y = 4)

6x - 8y = 8 ----------- eqn 4

<em><u>Subtract eqn 4 from eqn 3</u></em>

6x + 9y = 42

6x - 8y = 8

( - ) --------------

9y + 8y = 42 - 8

17y = 34

<h3>y = 2</h3>

<em><u>Substitute y = 2 in eqn 1</u></em>

2x + 3(2) = 14

2x + 6 = 14

2x = 14 - 6

2x = 8

<h3>x = 4</h3>

Thus the solution to given system of equations are (x, y) = (4, 2)

5 0
3 years ago
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