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taurus [48]
3 years ago
9

Convert 9.78 gallons toliters

Chemistry
2 answers:
Vika [28.1K]3 years ago
5 0

Answer:

44.46076 litres

Explanation:

REY [17]3 years ago
4 0

Answer:

about 37.02 Liters

Explanation:

The conversion rate is about 3.785. 9.78*3.785~37.02

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What mass of magnesium chloride is needed to make 100.0 mL of a solution that is 0.500 M in chloride ion?
miss Akunina [59]
M = n/V

.5M = n/.100 L

n = .1 L * .5M

n= .05 mols of MgCl2

mass of MgCl2 = .05 mols of MgCl2 * 95.211 grams/ 1 mol of MgCl2 

mass of MgCl2 = 4.76 grams

4.76 grams of MgCl2 is needed to make 100 ml of a solution that is .500M, in chloride ion. Bolded = confused
3 0
3 years ago
What is the empirical formula of a compound containing carbon, hydrogen, and oxygen in the ratio 14:42:84? C14H42O84
kati45 [8]
C:H:O = 14:42:84 = 7:21:42 = 1:3:6

CH₃O₆
6 0
3 years ago
Read 2 more answers
Which statement is true about the exothermic reaction?
Stells [14]

Answer:

C

Explanation:

The enthalpy of the reactants is greater than that of the products.

7 0
2 years ago
Convert 5.28 x 1019 molecules of C6H1206 to grams.
nlexa [21]

Answer:

m=0.0158g

Explanation:

Hello there!

In this case, it is possible to comprehend these mass-particles problems by means of the concept of mole, molar mass and the Avogadro's number because one mole of any substance has 6.022x10²³ particles and have a mass equal to the molar mass.

In such a way, for C₆H₁₂O₆, whose molar mass is about 180.16 g/mol, the referred mass would be:

m=5.28x10^{19}molecules*\frac{1mol}{6.022x10^{23}molecules}*\frac{180.16g}{1mol}\\\\m=0.0158g

Best regards!

5 0
3 years ago
Use the periodic table in the tools bar to answer these questions. How many moles of AgNO3 are present in 1.50 L of a 0.050 M so
IgorC [24]
M= moles de soluto / litros de solucion 
moles de soluto = M. litros de solucion 

Moles de soluto = 0.050 M x 1.50 L = 0.075 moles de AgNo3
4 0
3 years ago
Read 2 more answers
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