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3 years ago

Convert 9.78 gallons toliters

Chemistry

2 answers:

Vika [28.1K]3 years ago

5 0

Answer:

44.46076 litres

Explanation:

REY [17]3 years ago

4 0

Answer:

about 37.02 Liters

Explanation:

The conversion rate is about 3.785. 9.78*3.785~37.02

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Which transition in the hydrogen atom produces emitted light with the longest wavelength?

monitta

Answer:

Red light has the longest wavelength

Explanation:

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Hòa tan hoàn toàn 1,93 gam hỗn hợp 2 kim loại Fe và Al vào dd HCl dư, sau phản ứng thu được m gam muối và 1,456 lít khí H2 ở đkt

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Answer:

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For 100.0 mL of a solution that is 0.040M CH3COOH and 0.010 M CH3COO, what would be the pH after adding 10.0 mL 50.0 mM HCl?

damaskus [11]

Answer:

The pH of the buffer is 3.90

Explanation:

The mixture of a weak acid CH3COOH and its conjugate base CH3COO produce a buffer that follows the equation:

pH = pKa + log [A-] / [HA]

Where pH is the pH of the buffer, pKa is the pKa of acetic acid (4.75), and [A-] could be taken as the moles of the conjugate base and [HA] the moles of thw weak acid.

To solve this question we need to find the moles of the CH3COOH and CH3COO- after the reaction with HCl:

CH3COO- + HCl → CH3COOH + Cl-

The moles of CH3COO- are its initial moles - the moles of HCl added

And moles of CH3COOH are its initial moles + moles HCl added

Moles CH3COO-:

Initial moles = 0.100L * (0.010mol / L) = 0.00100moles

Moles HCl = 0.010L * (0.050mol / L) = 0.000500 moles

Moles CH3COO- = 0.000500 moles

Moles CH3COOH:

Initial moles = 0.100L * (0.040mol / L) = 0.00400moles

Moles HCl = 0.010L * (0.050mol / L) = 0.000500 moles

Moles CH3COO- = 0.003500 moles

pH is:

pH = 4.75 + log [0.000500] / [0.00350]

pH = 3.90

<h3>The pH of the buffer is 3.90</h3>

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3 years ago

What is the mass of 4.32 mol GaI3? 455 g 1,230 g 1,720 g 1,950 g

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Answer:

D. 1,950 g

Explanation:

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3 years ago

Purification of chromium can be achieved by electrorefining chromium from an impure chromium anode onto a pure chromium cathode

mylen [45]

Answer:

696 h

Explanation:

Let's consider the reduction of Cr³⁺.

Cr³⁺(aq) + 3e⁻ → Cr(s)

We can establish the following relations.

The molar mass of Cr is 52.0 g/mol.
1 mol of Cr is deposited when 3 moles of e⁻ circulate.
1 mole of e⁻ has a charge of 96468 c (Faraday's constant).
1 A = 1 c/s
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How many hours will it take to plate 13.5 kg of chromium onto the cathode if the current passed through the cell is held constant at 30.0 A?

$13.5 \times 10^{3} gCr.\frac{1molCr}{52.0gCr} .\frac{3mol/e^{-} }{1molCr} .\frac{96468c}{1mol/e^{-}} .\frac{1s}{30.0c} .\frac{1h}{3600s} =696 h$

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3 years ago