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2 years ago

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Chemistry

1 answer:

Angelina_Jolie [31]2 years ago

7 0

The mass of salt dissolved in 1.0 L of 0.010 M SO₄²⁻ is 0.67 g/l

<h3>How can we Calculate the mass of the salt dissolve in 1.0 L of 0.010 M SO₄²⁻ ?</h3>

To calculate the mass of the salt dissolved, we multiply by the mass of 1 mole to molar solubilty and lets assume we are using the anhydrous salt CaSO₄ for which the Molar Mass (M) = 136.1

Mass of the salt dissolved = Molar solubility x Molar mass

Molar Mass (M) = 136.1

Molar solubility = ?

Formula to find molar solubilty ;

Molar solubility = Square root of Solubity product (Given)

S = $\sqrt{2.4 x 10^{-5} }$ (Value of Solubity product is given in the question)

= 4.9 × 10⁻³

Mass of the salt dissolved = Molar solubility x Molar mass

= 4.9 × 10⁻³ x 136.1

= 0.67 g/l

Learn more about Solubility here ;

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You are performing a dilution of HBr going from a concentration of 12M to 0.335M, and you want to end up with a final volume of 75 ml of the dilute solution.

Consider the dilution formula: M1V1 = M2V2.

The basis behind this formula is that the number of moles of the acid before and after the dilution must remain constant.

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M2 = the molarity of the diluted solution,

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In this case, we need to determine V1, which is the volume of the stock solution used to prepare the diluted sample. With this knowledge, we can plug our numbers into the equation and we obtain the following:

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After rearranging the equation and solving for V1, we find that V1 = 0.00209L.

Finally, we must convert back from liters to mL by multiplying the final answer by 1000.

This way we end up with V1 = 2.09 mL.

This means that we need to add 2.09 mL of concentrated acid to obtain 75 mL of 0.335 M HBr solution.

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From the reaction, we conclude that

As, 4 mole of $C_3H_5(NO_3)_3$ react to give 12 mole of $CO_2$

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Now we have to calculate the mass of $CO_2$

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