Reference the following
1 answer:
The mass of salt dissolved in 1.0 L of 0.010 M SO₄²⁻ is 0.67 g/l
<h3>How can we Calculate the mass of the salt dissolve in 1.0 L of 0.010 M SO₄²⁻ ?</h3>To calculate the mass of the salt dissolved, we multiply by the mass of 1 mole to molar solubilty and lets assume we are using the anhydrous salt CaSO₄ for which the Molar Mass (M) = 136.1
Mass of the salt dissolved = Molar solubility x Molar mass
Molar Mass (M) = 136.1
Molar solubility = ?
Formula to find molar solubilty ;
Molar solubility = Square root of Solubity product (Given)
S = (Value of Solubity product is given in the question)
= 4.9 × 10⁻³
Mass of the salt dissolved = Molar solubility x Molar mass
= 4.9 × 10⁻³ x 136.1
= 0.67 g/l
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Answer:
Explanation:
From the given information:
TO start with the molarity of the solution:
= 0.601 mol/kg
= 0.601 m
At the freezing point, the depression of the solution is
Using the depression in freezing point, the molar depression constant of the solvent
The freezing point of the solution
The molality of the solution is:
Molar depression constant of solvent X,
Hence, using the elevation in boiling point;
the Vant'Hoff factor