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STatiana [176]
2 years ago
15

ΔXYZ was reflected over a vertical line, then dilated by a scale factor of One-half, resulting in ΔX'Y'Z'. Which must be true of

the two triangles? Select three options.
△XYZ ~ △X'Y'Z'
AngleXZY ≅ AngleY'Z'X'
YX ≅ Y'X'
XZ = 2X'Z'
mAngleYXZ = 2mAngleY'X'Z'
Mathematics
2 answers:
Nikolay [14]2 years ago
8 0

Answer:

∆XYZ ~∆X'Y'Z'

AngleXZY ≅ AngleY'Z'X'

XZ = 2X'Z'

Step-by-step explanation:

took test

pochemuha2 years ago
5 0

The options that are true of the triangles include:

  • ∆XYZ ~∆X'Y'Z'
  • AngleXZY ≅ AngleY'Z'X'
  • XZ = 2X'Z'

<h3>How to illustrate the triangle?</h3>

It should be noted that triangle XYZ is reflected over a vertical line. Then, it's dilated by 1/2 to form XYZ.

This implies that the triangles are similar, the angles are congruent and the side length of XYZ is twice that of X'Z.

Learn more about triangles on:

brainly.com/question/15481382

#SPJ1

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3 0
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Read 2 more answers
3-14 plzzz except #13 20 points!
Marianna [84]
#3: 15

#4: 13.2

#5: 5.44 (curious as to how you guessed 7)

#6: 7

#7: 7.3

#8: 15

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4 0
3 years ago
Convert the mixed number into a improper fraction 5 1/3
a_sh-v [17]

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Step-by-step explanation:

3 0
3 years ago
The length of 12cm and 5 cm missing one
alisha [4.7K]

Answer:

13cm

Step-by-step explanation:

Let the given lengths be the opposte amd adjacent sides of a right triangle'

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Using the pythagoras theorem;

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Hence the missing one is 13cm

5 0
3 years ago
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Answer:

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Step-by-step explanation:

Well first you would have to graph both inequalities.

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