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ivanzaharov [21]
2 years ago
7

One of the main components of hard water is CaCO3. When hard water evaporates, some of the CaCO3 is left behind as a white miner

al deposit. If a hard water solution is saturated with CaCO3, what volume of the solution has to evaporate ot deposit 1*10^{2} mg of CaCO3?
Chemistry
1 answer:
Digiron [165]2 years ago
6 0
My source says the Ksp of CaCO3 at 25 C is 8.7 X 10^-9 

Ksp = [Ca++][CO3--] = 8.7 X 10^-9 

Let "X" = the solubility; then: 

X^2 = 8.7 X 10^-9 

X = 9.33 X 10^-5 M 

Mol. mass CaCO3 = 40 + 12 + 3(16) = 100 g / mole 

Solubility CaCO3 = (100 g / mole)(9.33 X10^-5 mole / liter) = 9.33 X 10^-3 g liter or 9.33 mg / liter 

Volume of CaCO3 solution = 1.00 X 10^2 mg / 9.33 mg / liter = 10.7 liters 

<span>Answer: 10.7 liters


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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If the chemist mistakenly makes 250 mL of solution instead of the 200 mL, what molar concentration of sodium nitrate will the ch
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Answer:

0.120M is the concentration of the solution

Explanation:

<em>Assuming the mass of sodium nitrate dissolved was 2.552g</em>

<em />

Molar concentration is an unit of concentration widely used in chemsitry defined as the moles of solute (In this case NaNO3) in 1L of solution.

To find this question we must find the moles of NaNO3 in 2.552g. With this mass and the volume (250mL = 0.250L) we can find molar concentration as follows:

<em>Moles NaNO3 -Molar mass: 84.99g/mol-</em>

2.552g * (1mol / 84.99g) = 0.0300 moles NaNO3

<em>Molar concentration:</em>

0.0300 moles NaNO3 / 0.250L =

<h3>0.120M is the concentration of the solution</h3>
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3 years ago
Homeostasis means maintaining
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Explanation:

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1) Given the balance equation below. Calculate how much Na3PO4 in grams you
juin [17]

Answer:

<u>136.67 g of Na3PO4 i</u>s required to create 100 gram of NaOH.

Explanation:

The balanced equation:

Na_{3}PO_{4} + 3 KOH \rightarrow 3 NaOH + K_{3}PO_{4}

1 mole Na3PO4 = 164 g/mole (Molar mass)

1 mole NaOH = 40 g/mole (Molar mass)

Now,

1 mole of Na3PO4 produce = 3 mole of NaOH

164 g/mol of Na3PO4 produce = 3(40) g/mol of NaOH

or

120 g/mol of NaOH is produced from = 164 g/mol of Na3PO4

1 g/mol of NaOH is produced from =

\frac{164}{120}

100 grams of NaOH is produced from =

\frac{164}{120}\times100 gram of Na3PO4

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= 136.67 g

8 0
3 years ago
The ksp value for lead(ii chloride is 2.4 × 10?4. what is the molar solubility of lead(ii chloride?
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Molar solubility is number of moles of the solute that can be dissolved per liter of solution before the solution becomes saturated. 

The molar solubility of lead(ii) chloride with ksp value of 2.4 × 10e4 can be solve as: 

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s2 = 2.4 × 10e4
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