A bicyclist moving at a constant speed takes 10.0 seconds to travel 500 meters down a path inclined 30.0° downward from the horizontal. the vertical velocity of this motion is mathematically given as
V' = 25 m/s. Option C.
<h3>What is the vertical velocity of this motion?</h3>Generally, the equation for the Inclined Component is mathematically given as
V=d/s
Therefore
V = 500/10
V= 50 m/s
In conclusion, for the vertical Component
V'= 50Sin30
V' = 25 m/s
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Answer:19.5 J
Explanation:
Given
mass of block=3 kg
angular frequency=20 rad/sec
spring constant
we know total energy remain conserved
Where =kinetic energy
=potential Energy
When mass reaches amplitude its velocity becomes zero
there is only potential energy which is equal to Total energy
Answer:
v₂ = 176.24 m/s
Explanation:
given,
angle of projectile = 45°
speed = v₁ = 150 m/s
for second trail
speed = v₂ = ?
angle of projectile = 37°
maximum height attained formula,
now,
now, equating both the equations
v₂² = 31061.79
v₂ = 176.24 m/s
velocity of projectile would be equal to v₂ = 176.24 m/s