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3 years ago

In a displacement versus time graph, what does the slope of a line at any point indicate?

Physics

2 answers:

Gennadij [26K]3 years ago

5 0

Answer:

its acceleration

Explanation:

Rom4ik [11]3 years ago

4 0

In a displacement versus time graph, the slope of the line at any point on the graph indicates the magnitude of velocity.

(It can't indicate velocity completely, because the graph shows nothing about the direction of the motion.)

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If the satellite has a mass of 3900 kg , a radius of 4.3 m , and the rockets each add a mass of 210 kg , what is the required st

ehidna [41]

Answer:

The required steady force of each rocket is 28.79 N

Explanation:

mass of the satellite, M=3900 kg

radius, r=4.3 m

mass of rocket, m=210 kg

time, t=5.4 min

Moment of Inertia:

I = 1/2 (Mr^2) + 4mr^2

I = 1/2 ( 3900* (4.3)^2) + 4 (210)*(4.3)^2

I = 51587.1 kg m^2

the angular acceleration is:

a= w/t

here w= 2*π*30

so,

a= 2*π*30 / 5.4* 3600

a=0.0096 rad/ s^2

the Torque becomes:

T=I*a = 4r*F

( 51587.1 )*(0.0096) = 4*4.3* F

F= 28.79 N

the required steady force of each rocket is 28.79 N

learn more about steady force here:

brainly.com/question/13841147

#SPJ4

7 0

1 year ago

A large, 34.0 kg bell is hung from a wooden beam so it can swing back and forth with negligible friction. The bell's center of m

Lorico [155]

Answer:

length L of the clapper rod for the bell to ring silently = 0.756m

Explanation:

We are given;

Mass of Bell;m_b = 34 kg

Distance of centre of mass from pivot;d = 0.7m

The bells moment of inertia about an axis at the pivot;I = 18 kg.m²

Mass of clapper;m_c = 1.8 kg

Length of slender rod is L

Now, the formula for period of physical pendulum having small amplitude is given as;

T_b = 2π√(I/mgd)

Where;

I is moment of inertia

m is mass

g is acceleration due to gravity = 9.8 m/s²

d is distance from rotation axis to centre of gravity

Plugging in the relevant values and using mass of bell, we have;

T_b = 2π√(18/(34*9.81*0.7)

T_b = 1.745 s

Now, the formula for period for a simple pendulum which is essentially what the clapper rod is would be;

T_c = 2π√(L/g)

Now, we want to find length of clapper L.

Thus, let's make it the subject;

L = g(T_c/2π)²

Now, we are told that for the bell to ring silently, T_b = T_c.

Thus, T_c = 1.745 s.

So,

L = 9.8(1.745/2π)²

L = 0.756m

7 0

3 years ago

What vaciole-like strucyure break down and recycle cell parts

kap26 [50]

lysosomes should be the right answer to this question

6 0

3 years ago

A spring that is compressed 14.5 cm from its equilibrium position stores 2.99 J of potential energy. Determine the spring consta

strojnjashka [21]

Answer:

284.4233 N/m

Explanation:

k = Spring constant

x = Compression of spring = 14.5 cm

U = Potential energy = 2.99 J

The potential energy of a spring is given by

$U=\dfrac{1}{2}kx^2$

Rearranging to get the value of k

$\\\Rightarrow k=\dfrac{2U}{x^2}\\\Rightarrow k=\dfrac{2\times 2.99}{0.145^2}\\\Rightarrow k=284.4233\ N/m$

The spring constant is 284.4233 N/m

7 0

3 years ago

g When a high-energy proton or pion traveling near the speed of light collides with a nucleus, it may travel 3.2 10-15 m before

AnnyKZ [126]

Answer:

Time, $t=1.07\times 10^{-23}\ s$

Explanation:

Given that,

When a high-energy proton or pion traveling near the speed of light collides with a nucleus, it may travel $3.2\times 10^{-15}\ m$ before interacting.

Let t is the time interval required for the strong interaction to occur. It will move with the speed of light. So,

$t=\dfrac{d}{c}\\\\t=\dfrac{3.2\times 10^{-15}}{3\times 10^8}\\\\t=1.07\times 10^{-23}\ s$

So, the time interval is $1.07\times 10^{-23}\ s$

5 0

3 years ago