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daser333 [38]
2 years ago
6

The level of closeness between a measured quantity and the actual or standard value is called what?

Physics
2 answers:
bija089 [108]2 years ago
7 0

Answer:

  D.

accuracy

Explanation:

Amanda [17]2 years ago
4 0

Answer:

precision

Explanation:

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When the only force acting on a falling object is air resistance, the object is said to be in free fall. true or false.?
Nimfa-mama [501]
When the only force acting on a falling object is air resistance, the object is said to be In free fall. TRUE
7 0
3 years ago
A 200 g air-track glider is attached to a spring. The glider is pushed in 9.8 cm against the spring, then released. A student wi
Likurg_2 [28]

Answer:

k =  5.05 N/m

Explanation:

In order to calculate the spring mass of the system, you use the following formula:

T=2\pi \sqrt{\frac{m}{k}}     (1)

T: period of oscillation of the system

m: mass of the air-track glider = 200g = 0.200 kg

k: spring constant = ?

You first calculate the period of oscillation:

T=\frac{1}{f}=\frac{1}{12/15.0s}=1.25s

Next, you solve the equation (1) for k, and then you replace the values of the other parmateres:

k=4\pi^2 \frac{m}{T^2}\\\\k=4\pi^2 \frac{0.200kg}{(1.25s)^2}=5.05\frac{N}{m}

The spring constant of the spring is 5.05 N/m

6 0
2 years ago
How to calculate wavelength in m when you know the frequency?
NNADVOKAT [17]
It's c/f, in which c is the speed of light (300000 m/s)
6 0
2 years ago
Substances which naturally attract each other called what
grandymaker [24]

Answer:

Ferromagnetism, physical phenomenon in which certain electrically uncharged materials strongly attract others. Two materials found in nature, lodestone (or magnetite, an oxide of iron, Fe3O4) and iron, have the ability to acquire such attractive powers, and they are often called natural ferromagnets.

Hope this help :)

5 0
2 years ago
1. A 25.35-g piece of iron absorbs 1562.75 Joules of heat energy, and its temperature
Lera25 [3.4K]

Answer:

Q = C M T        where C is the specific, M the mass, T the temperature change

Note 1 cal = 4.19 Joules

1562.75 J / (4.19 J/cal) = 378 cal

C = Q / (M * T) = 378 cal / (25.35 g * 155 deg C)

C = .096 cal / g deg C

8 0
1 year ago
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