The distance between the charges is 13.86 X 10⁴m
<u>Explanation:</u>
Given:
Force, F = 1.2N
Charge, q₁ = 1.602 X 10⁻¹⁹ C
k = 8.987 X 10⁹ Nm²/C²
Distance, d = ?
According to Coulomb's law:

Substituting the value in the formula we get:

Therefore, the distance between the charges is 13.86 X 10⁴m
Answer:
When a ray of light falls on a glass slab normally, the angle between normal and incident ray is zero.
The answer is no, it would be impossible to see the beginning of the universe
Answer:
The new distance is d = 0.447 d₀
Explanation:
The electric out is given by Coulomb's Law
F = k q₁ q₂ / r²
This electric force is in balance with tension.
We reduce the charge of sphere B to 1/5 of its initial value (
=q₂ = q₂ / 5) than new distance (d = n d₀)
dat
q₁ = 
q₂ = 
r = d₀
In order for the deviation to maintain the electric force it should not change, so we apply the Coulomb equation for the two points
F = k q₁ q₂ / d₀²
F = k q₁ (q₂ / 5) / (n d₀)²
.k q₁ q₂ / d₀² = q₁ q₂ / (5 n² d₀²)
5 n² = 1
n = √ 1/5
n = 0.447
The new distance is
d = 0.447 d₀
Answer:
8.467 gm
Explanation:
The law governing this problem is "The Law of Constant Composition "
As per this law, all compounds irrespective of their origin and source have the same composition and properties in their purest form
It is a simple proportion and ratio related problem.
1.50 grams of carbon require 2.0 grams of oxygen
1.0 grams of carbon will require oxygen
=
6.35 grams of carbon will require oxygen
= 8.4666\\= 8.467