How many moles of a gas are contained in 2.085 L at STP?
1 answer:
Answer /-
A.0.0931 mol
from ideal gas equation ,
We have ,
PV = nRT
Where P stands where pressure of gas.
We know that pressure of gas at STP = 1 atm
V stands for volume of gas , given Volume is 2.085 L
R stands for gas constant , R = 0.0821
And T stands for absolute temperature and measured in kelvin,T=273K
Now ,
PV = nRT
n = PV/RT
Refer attachment for working
A.0.0931 mol
from ideal gas equation ,
We have ,
PV = nRT
Where P stands where pressure of gas.
We know that pressure of gas at STP = 1 atm
V stands for volume of gas , given Volume is 2.085 L
R stands for gas constant , R = 0.0821
And T stands for absolute temperature and measured in kelvin,T=273K
Now ,
PV = nRT
n = PV/RT
Refer attachment for working
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Answer:
Explanation:
The volume and amount are constant, so we can use Gay-Lussac’s Law:
At constant volume, the pressure exerted by a gas is directly proportional to its temperature.
Data:
p₁ = 1520 Torr; T₁ = 27 °C
p₂ = ?; T₂ = 150 °C
Calculations:
(a) Convert the temperatures to kelvins
T₁ = ( 27 + 273.15) K = 300.15 K
T₂ = (150 + 273.15) K = 423.15 K
(b) Calculate the new pressure
(c) Convert the pressure to atmospheres