How many moles of a gas are contained in 2.085 L at STP?

1 answer:

muminat2 years ago

4 0

Answer /-

A.0.0931 mol

from ideal gas equation ,

We have ,

PV = nRT

Where P stands where pressure of gas.
We know that pressure of gas at STP = 1 atm

V stands for volume of gas , given Volume is 2.085 L

R stands for gas constant , R = 0.0821

And T stands for absolute temperature and measured in kelvin,T=273K

Now ,

PV = nRT

n = PV/RT

Refer attachment for working

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