Answer:
I cant answer B, but I can answer A, and I don't think it is a scientifically reasonable plan.
Explanation:
The bag of sand weighs less than the gold statue, and yes the bag of sand seems like it would keep the trap from activating, but you would scientifically have to put something that was the same weight as the gold statue on the pedestal that the statue is on.
Answer:
Eukarya- Multicellar and unicellar
Explanation:
Fugi- Multicellar
Protista- unicellar
eubacteria- unicellar and have no nucleus
Eukarya is the only option, and that is because Eukarya is both! It contains a nucleus, and a membrane making it the only one that fits into the incomplete graphic! Hope this helps! (I noticed you were waiting for a while so I came to help! <3)
The activity series of metals as well as the electrode potential of metals can be used to compare the reactivity of metals.
<h3>What is used in comparing reactivity of metals?</h3>
The reactivity of metals can be compared using their electrode potentials which is a measures of the ability of the metal to donate electrons to another metal.
When comparing the reactivity of metals, the metal with the lesser negative electrode potential will be more reactive than another with a greater negative or positive electrode potential.
Therefore, the activity series of metals as well as the electrode potential of metals can be used to compare the reactivity of metals.
Learn more about activity series of metals at: brainly.com/question/17469010
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<span>Dry ice is frozen carbon dioxide. It is easy to assume that the fog surrounds dry ice is carbon dioxide returning to it's gaseous however, you can not see that process. The vapors you see is the water molecules in the air condensing as a result of the cooling or energy removal by the dry ice. When energy is removed from water molecules they become colder and move slower than water in a gaseous. Similar to clouds in the air, the water condenses into a form that you can see.</span>
Answer:
Keqq = 310
Note: Some parts of the question were missing. The missing values are used in the explanation below.
Explanation:
<em>Given values: ΔH° = -178.8 kJ/mol = -178800 J/mol; T = 25°C = 298.15 K; ΔS° = -552 J/mol.K; R = 8.3145 J/mol.K</em>
Using the formula ΔG° = -RT㏑Keq
㏑Keq = ΔG°/(-RT)
where ΔG° = ΔH° - TΔS°
㏑Keq = ΔH° - TΔS°/(-RT)
㏑Keq = {-178800 - (-552 * 298.15)} / -(8.3145 * 298.15)
㏑Keq = -14221.2/-2478.968175
㏑Keq = 5.73674166
Keq = e⁵°⁷³⁶⁷⁴¹⁶⁶
Keq = 310.05