Just give me answer

Mathematics

2 answers:

atroni [7]2 years ago

6 0

By applying the equation of dilation, the coordinates of the vertices of the triangle ABC are A'(x, y) = (-12, 0), B'(x, y) = (0, -9) and C'(x, y) = (-12, -9).

<h3>How to find the image of a triangle</h3>

A dilation is a type of <em>rigid</em> transformation. <em>Rigid</em> transformations are transformations applied to <em>geometric</em> loci such that <em>Euclidean</em> distances are conserved.

There is a triangle and its image must be a triangle, the <em>new</em> triangle is found by transforming the three vertices of the prior one following this formula:

A'(x, y) = P(x, y) + k · [A(x, y) - P(x, y)] (1)

Where:

P(x, y) - Center of reflection.
A(x, y) - Original vertex
A'(x, y) - New vertex
k - Dilation factor

If we know that P(x, y) = (0, 0), A(x, y) = (-4, 0), B(x, y) = (0, -3) and C(x, y) = (-4, -3), then the new vertices of the triangle are, respectively:

Point A

A'(x, y) = (0, 0) + 3 · [(-4, 0) - (0, 0)]

A'(x, y) = (-12, 0)

Point B

B'(x, y) = (0, 0) + 3 · [(0, -3) - (0, 0)]

B'(x, y) = (0, -9)

Point C

C'(x, y) = (0, 0) + 3 · [(-4, -3) - (0, 0)]

C'(x, y) = (-12, -9)

Lastly, we draw the two triangles, which are presented in the image attached below.

To learn more on dilations: brainly.com/question/13176891

#SPJ1

Vikki [24]2 years ago

5 0

<h3><em>im giving answer right?.. i think</em></h3>

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Find the slope of the line that passes through (6, 7) and (2, 10). and simplify if needed thx guys.

tekilochka [14]

Answer:

$-\frac{3}{4}$

Step-by-step explanation:

the equation for finding the slope of a line when given two points is $\frac{y_2-y_1}{x_2-x_1}$ , aka the change in y over the change in x.

pick one of your coordinate pairs to be $y_2\\$ and $x_2$ . it doesn't matter which coordinate pair you choose as long as you keep them as $y_2\\$ and $x_2$ . the remaining coordinate pair will be $y_1$ and $x_1$ .

for this example, i'll use (2, 10) for $y_2\\$ and $x_2$ and (6, 7) for $y_1$ and $x_1$ .

<em>**before i begin, i just want to note that you can do these next four steps in any order that you want. i personally prefer to plug in my y-values first and then my x-values, but you can choose to instead plug in the values of each coordinate pair (like starting by plugging in the coordinate pair (2, 10) with 10 for </em> $y_2\\$ and 2 for $x_2$ <em>). it's up to you. i'm going to explain the steps by plugging in my y-values first and then my x-values because that's the way i normally do it.</em>

<em />

first, start by plugging in the y-value from the coordinate pair of your choosing in for $y_2\\$ . since i chose (2, 10) for $y_2\\$ and $x_2$ , i'll plug in 10 for $y_2\\$ .

$\frac{y_2-y_1}{x_2-x_1}$ ⇒ $\frac{10-y_1}{x_2-x_1}$