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Lynna [10]
3 years ago
7

Which element has the largest difference between the third ionization and the fourth ionization?

Chemistry
1 answer:
dolphi86 [110]3 years ago
7 0
Iron has the largest difference
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What makes a metal and a non metal most
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Explanation:

The reactivity of elements in the periodic table is based on the number of electrons in there outermost shell. Elements (metals) that have few electrons in there outermost shell are highly reactive because it is easier to lose fewer number of electrons (in the outermost shell during a reaction) than to lose more electrons in the outermost shell - thus metals that have one electron in there outermost shell are most reactive and are more reactive than those that have two electrons in there outermost shell. Hence, metals in group 1 are the most reactive metals because they all have one electron in there outermost shell.

Non-metals that have fewer electrons to complete there octet configuration are highly reactive because it is easier to gain fewer number of electrons (in the outermost shell during a reaction) than to gain more number of electrons - thus nonmetals that have seven electrons in there outermost shell are more reactive than nonmetals that have six electrons in there outermost shell. Hence, nonmetals in group 17 are the most reactive nonmetals because they contain seven electrons and have just one electron left to complete there octet configuration.

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3 years ago
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3 years ago
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If molten sodium chloride is split by electrolysis, which reaction occurs at the anode?
mariarad [96]

Answer: 2Cl^-(l)\rightarrow 2e^-+Cl_2(g)

Explanation:

Electrolysis of a subastance is breaking it into its constituents by the action of electrical current.  

In the electrolysis of molten sodium chloride, sodium metal is produced at the cathode which is a negative electrode and chlorine gas produces as the anode which is a positive electrode.

2NaCl(l)\rightarrow 2Na^++2Cl^-

At anode : 2Cl^-(l)\rightarrow 2e^-+Cl_2(g)

At cathode : 2Na^+(l)+2e^-\rightarrow 2Na(l)

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I really hope this helped :)

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