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PtichkaEL [24]
2 years ago
8

Action and reaction forces are described by which of Newton’s laws of motion?

Physics
1 answer:
nikdorinn [45]2 years ago
5 0

Answer:

third

Explanation:

for every action there is an equal and opposite reaction

example

bouncing ball

ball receives a force from the ground due to collision

that same force causes the ball to bounce off the ground

first law:

inertia

example

stuff in space doesn't move unless its pushed

then it keeps going unless something stops it

second law

force = mass times acceleration

example

harder you push a cart the faster it goes

the less a cart weighs the faster a cart goes

studysmarterus

spacecenterorg

energywavetheory

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If an object falls from rest and lands 3.2 seconds later, how many<br> meters did it fall
DIA [1.3K]

Answer:

50.2 meters

Explanation:

When an object falls, it goes a distance d in time t according to the formula:

d=\frac{1}{2}*g*t^{2}

d is the distance in meter, g is the acceleration due to gravity with the value of 9.8m/s^{2} , t is the time in seconds

Therefore, d = \frac{1}{2}*9.8*(3.2)^{2}

d= 50.176 ≈ 50.2m

6 0
3 years ago
what are the two angles of a projection of a projectile moving with the velocity is 20m/s. so that the horizontal range is 45m​
GREYUIT [131]

Answer:

Answer. So, the two Angles R :- 15° and 75° .

7 0
3 years ago
Calculate the average speed (in km/h) of a car stuck in traffic that drives 12 kilometers in 2 hours.
Vilka [71]
This is a trick question, isn't it? If a car is stuck in traffic, it doesn't matter how fast it can travel, because it isn't moving at all. Therefore the average speed would be zero, right?
7 0
4 years ago
A uniform ladder of length L and weight w is leaning against a vertical wall. The coefficient of static friction between the lad
pantera1 [17]

Answer: 45.3°

Explanation:

Given,

Length of ladder = l

Weight of ladder = w

Coefficient of friction = μs = 0.495

Smallest angle the ladder makes = θ

If we assume the forces in the vertical direction to be N1, and the forces in the horizontal direction to be N2, then,

N1 = mg and

N2 = μmg

Moment at a point A in the clockwise direction is

N2 Lsinθ - mg.(L/2).cosθ = 0

μmgLsinθ - mg.(L/2).cosθ = 0

μmgLsinθ = mg.(L/2).cosθ

μsinθ = cosθ/2

sin θ / cos θ = 1 / 2μ

Tan θ = 1 / 2μ

Substituting the value of μ = 0.495, we have

Tan θ = 1 / 2 * 0.495

Tan θ = 1 / 0.99

Tan θ = 1.01

θ = tan^-1(1.01)

θ = 45.3°

3 0
3 years ago
50 POINTS! A Boy throws a ball horizontally a distance of 22m downrange from the top of a tower that is 20.0m tall. What is his
DerKrebs [107]

The ball's horizontal and vertical velocities at time t are

v_x=v_{xi}

v_y=v_{yi}-gt

but the ball is thrown horizontally, so v_{yi}=0. Its horizontal and vertical positions at time t are

x=v_{xi}t

y=20.0\,\mathrm m-\dfrac g2t^2

The ball travels 22 m horizontally from where it was thrown, so

22\,\mathrm m=v_{xi}t

from which we find the time it takes for the ball to land on the ground is

t=\dfrac{22\,\rm m}{v_{xi}}

When it lands, y=0 and

0=20.0\,\mathrm m-\dfrac{9.8\frac{\rm m}{\mathrm s^2}}2\left(\dfrac{22\,\rm m}{v_{xi}}\right)^2

\implies v_i=v_{xi}=11\dfrac{\rm m}{\rm s}

7 0
3 years ago
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