Three metal spheres are placed as shown in the image. Sphere A weighs 5 kg, B weighs 8 kg, and C weighs 3 kg.

The imaginary line from the tip of the football to the football to the sideline is called

pentagon [3]

The imaginary line from the tip of the football to the football to the sideline is called Line of Scrimmage. I believe.

8 0

2 years ago

Exercise can help to prevent which potential health problem? a). head lice b). chicken pox c). heart disease d). strep throat

Mrac [35]

Answer:

C

Explanation:

Exercise also increases your levels of HDL cholesterol, the "good" cholesterol that lowers heart disease risk by flushing the artery-clogging LDL or "bad" cholesterol out of your system.

5 0

2 years ago

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The rate at which temperature decreases with height in the atmosphere is called the

Genrish500 [490]

It is called <span>environmental lapse rate</span>

5 0

3 years ago

A stone whirled at the end of the a rope 30cm long, makes 10 complete resolution in 2 seconds Find: A. The angular velocity in r

lord [1]

Answers:

A: Angular velocity $\omega=31.40 \frac{r a d}{s}$

B: Linear velocity $v=9.42 \frac{m}{s}$

C: Linear Distance $d=47.1 \mathrm{m}$

Given:

Radius of the rope r=30cm=0.3m

Angular distance $\Delta \theta$ =10 revolutions

Time taken t=2seconds

To find:

A: Angular velocity in radians

B: Linear speed

C: Distance covered in 5 seconds

<u>Step by Step Explanations:</u>

Solution:

A: Angular velocity in radians;

According to the formula, Angular velocity can be calculated as

Angular Velocity = angular distance/ time

$\omega=\Delta \theta / \Delta t$

Where $\omega$ =Angular velocity

$\Delta \theta$ =Angular distance=10 revolutions

Changing revolutions to radians multiply with $2 \pi$ , so that we get

$=10 \times 2 \pi$

$=10 \times 2(3.14)$

=62.80 rad/rev

$\Delta t$ =Change in time

Substitute the known values in the above equation we get

$\omega$ =62.80 / 2

$\omega=31.40 \frac{r a d}{s}$

B. Linear speed of the rope;

As per the formula

Linear speed = angular speed × radius

$v=\omega \times r$

Where $\omega$ =Angular velocity

v=Linear speed of the rope

r=Radius of the rope

Substitute the known values in the above equation we get

$v=31.40 \times 0.30$

$v=9.42 \frac{m}{s}$

C. Dsitance covered in 5 seconds;

Linear distance = linear speed × time

$d=v \times t$

Where d= Linear distance of the rope

v=Linear speed of the rope

t=Time taken

Substitute the known values in the above equation we get

$d=9.42 \times 5$

$d=47.1 \mathrm{m}$

Result:

Thus A: Angular velocity of the rope $\omega=31.40 \frac{r a d}{s}$

B Linear speed of the rope $v=9.42 \frac{m}{s}$

C: Distance covered in 5 seconds $d=47.1 \mathrm{m}$

6 0

2 years ago

What are the differences between the plum pudding model, nuclear model and the atomic model

kakasveta [241]

The plum pudding model suggested that the electrons were dispersed throughout the atom (like chocolate chips in a cookie) and the space was positively charged so that in the end the atom was neutral. Today, people know that the electrons are in a "cloud" around the atom and the protons (and neutrons) are in the nucleus, at the center of the atom.

7 0

2 years ago

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