Answer:
-45
Step-by-step explanation:
For this you count rise over run aka how many up divided by how many over starting from 0. here it’s 7 up and 3.5 side, 7 divided by 3.5 is 2 and the line is going down so it’s negative 2 (D)
When you divide two fractions, you do Keep, Change, Flip or KCF. So you keep the 3/5, you change the division sign to a multiplication sign, then flip the 3/15 to 15/3. So the new equation is 3/5x15/3. Then you simply the two sides so it becomes 1/1x3/1.....
Meaning the answer is 3.
Missing information:
How fast is the temperature experienced by the particle changing in degrees Celsius per meter at the point

Answer:

Step-by-step explanation:
Given




Express the given point P as a unit tangent vector:

Next, find the gradient of P and T using: 
Where

So: the gradient becomes:

![\triangle T = [(sin \sqrt 3)i + (cos \sqrt 3)j] * [\frac{\sqrt 3}{2}i - \frac{1}{2}j]](https://tex.z-dn.net/?f=%5Ctriangle%20T%20%3D%20%5B%28sin%20%5Csqrt%203%29i%20%2B%20%28cos%20%5Csqrt%203%29j%5D%20%2A%20%20%5B%5Cfrac%7B%5Csqrt%203%7D%7B2%7Di%20-%20%5Cfrac%7B1%7D%7B2%7Dj%5D)
By vector multiplication, we have:




Hence, the rate is:
I think it would be 117
Because H is 63
So 90+90+63=243
360-243=117
I used 360 because angles in quadrilaterals add up to 360 degrees