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ohaa [14]
3 years ago
13

Consider the three inclines shown in the figure. The vertical line is an incline with a 90° angle. (Inclines with 90° angles do

exist!) All three inclines are frictionless. Three small identical objects are released from the top of the inclines. What can we tell about their travel times and final speeds?
(Options are: greater than, less than, equal to)

The final speed of C is ... that of B.

The travel time of A is ... that of B.

The final speed of B is ... that of A.

The travel time of C is ... that of B.

The final speed of A is ... that of C.

The travel time of C is ... that of A.
Physics
1 answer:
const2013 [10]3 years ago
4 0

The final speed of C is equal to that of B.

The travel time of A is less than that of B.

The final speed of B is equal to that of A.

The travel time of C is greater than that of B.

The final speed of A is equal to that of C.

The travel time of C is greater than that of A.

<h3>What is speed?</h3>

The speed of any moving object is the ratio of the distance covered and the time taken to cover that distance.

Consider the three inclines shown in the figure (attached below). The vertical line is an incline with a 90° angle. All three inclines are frictionless. Three small identical objects are released from the top of the inclines.

When the objects are at the same height, they travel with the same height. The travel time is directly proportional to the incline.

Thus, all the statements are completed.

Learn more about speed.

brainly.com/question/7359669

#SPJ1

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If magma is defined as molten rock material,do you need to melt rocks to form magma?<br>​
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50 N Vertical 10 N Horizontal Force X can you find force x?<br>​
malfutka [58]

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45

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3 0
3 years ago
A car moving with an initial speed of 25 m/s slows down to a speed of 5 m/s in 10 seconds Calculate a) the acceleration of the c
stealth61 [152]

Answer :

(a) The acceleration  of the car is, -2m/s^2

(b) The distance covered by the car is, 150 m

Explanation :  

By the 1st equation of motion,

v=u+at ...........(1)

where,

v = final velocity = 5 m/s

u = initial velocity  = 25 m/s

t = time = 10 s

a = acceleration  of the car = ?

Now put all the given values in the above equation 1, we get:

5m/s=25m/s+a\times (10s)

a=-2m/s^2

The acceleration  of the car is, -2m/s^2

By the 2nd equation of motion,

s=ut+\frac{1}{2}at^2 ...........(2)

where,

s = distance covered by the car = ?

u = initial velocity  = 25 m/s

t = time = 10 s

a = acceleration  of the car = -2m/s^2

Now put all the given values in the above equation 2, we get:

s=(25m/s)\times (10s)+\frac{1}{2}\times (-2m/s^2)\times (10s)^2

By solving the term, we get:

s=150m

The distance covered by the car is, 150 m

8 0
3 years ago
A certain siren radiates sound uniformly in all directions. At a distance of 17 m from the siren, the intensity level is 49 db.
AveGali [126]

Answer:

The power is  P =  2.88*10^{-4 } \ W

Explanation:

From the question we are told that

   The distance from the siren  is  d =  17 \ m

  The intensity level is  \beta  =  49\ dB

   The threshold of hearing is   I_0 = 1.0 *10^{-12} \ W/m^2

Generally the intensity level is mathematically represented as

      \beta  =  10dB * log [\frac{I}{I_o} ]

Where I is the intensity at which the siren radiates the sound

substituting values  

       49  =  10 * log [\frac{I}{1.0 *10^{-12}} ]

=>    I  =  7.94*10^{-8} W/m^2

Now the amount of power the siren put out is mathematically evaluated as

      P= IA

Where A is the area  of the siren which is taken as a sphere  and it  is mathematically evaluated as

       A =  4 \pi d^2

So  

     P =  I  * 4 \pi d^2

substituting values

    P =  7.94 *10^{-8}  * 4  * 3.142 * (17)^2

   P =  2.88*10^{-4 } \ W

3 0
3 years ago
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