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kiruha [24]
3 years ago
15

Which of the following pairs does not share the same empirical formula? C2H6 and C6H18 C3H6O3 and C2H4O2 C3H6 and CH4 CH2O and C

3H6O3
Chemistry
2 answers:
DerKrebs [107]3 years ago
7 0

Answer:

c) C₃H₆ and CH₄

Explanation:

The empirical formula is obtained from a molecular formula by dividing it with a whole number with which all elements are divisible completely. Empirical formula is the simplest ratio of all the elements present in a molecule.

Let us consider all the examples

a) C₂H₆ and C₆H₁₈

Empirical formula of C₂H₆ = CH₃[by dividing with two]

Empirical formula of C₆H₁₈= CH₃ [by dividing with six]

b) C₃H₆O₃and C₂H₄O₂

Empirical formula of C₃H₆O₃ = CH₂O[by dividing with three]

Empirical formula of C₂H₄O₂= CH₂O [by dividing with two]

c) C₃H₆ and CH₄

Empirical formula of C₃H₆ = CH₂[by dividing with three]

Empirical formula of CH₄= CH₄ [already simplest ratio]

So these are not same.

d) CH₂O and C₃H₆O₃

Empirical formula of C₃H₆O₃ = CH₂O[by dividing with three]

Empirical formula of CH₂O= CH₂O [already simplest ratio]

denpristay [2]3 years ago
3 0
C3H6 and CH4

The empirical number is found by looking at the ratio of the numbers. For example, H20 and H402 have the same empirical formula because the ratio remained similar. 2 H to 1 O. 
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statuscvo [17]

Answer:

₁₅P = 1s² 2s² 2p⁶ 3s² 3p³

Explanation:

Phosphorus is the second element of group (v) with atomic number 15 and the electrons per shell are arrange as thus; 2, 8, 5.

The electronic configuration of phosphorus is

₁₅P = 1s² 2s² 2p⁶ 3s² 3p³

Or

₁₅P [Ne] 3s² 3p³

In its first shell I.e 1s shell, it has 2 electrons filling it to s-orbital requirement. In its second shell, electrons fill it in 2s² 2p⁶ filling the second orbital and attaining an octet configuration. The third shell contains 5 electrons filling 3s² 3p³ orbital.

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3 years ago
Give the name and formula of the compound formed from the following elements:<br> (b) ₃₀L and ₁₆M
madam [21]

When sulfur reacts with zinc metal is forms a compound known as zinc sulfide.

<h3>Name of the elements</h3>

The names of the elements that make up the compound will be determined from the atomic mass of the elements.

<h3>Which element has atomic number 30</h3>

The element that atomic number of 30 is zinc and it has oxidation number of +2.

<h3>Which element has atomic number 16</h3>

The element that atomic number of 16 is sulfur and it has oxidation number of -2.

<h3>Chemical reaction between sulfur and zinc metal</h3>

Zn²⁺ + S²⁻  --------> ZnS

Thus, when sulfur reacts with zinc metal is forms a compound known as zinc sulfide.

Learn more about zinc sulfide here: brainly.com/question/20806552

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8 0
1 year ago
Help I’m so confused
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Answer:

Me too.  What is this for? A Lab. You are missing some kind of key info bud.

Explanation:

4 0
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1-Bromopropane is treated with each of the following reagents. Draw the major substitution product if the reaction proceeds in g
sammy [17]

Answer:

Explanation:

If we look at the structure of 1-Bromopropane; we will see that it is a derivative of alkane family by the the substitution of an alkyl group. The position of the Bromine in the propane is 1, making 1-Bromopropane  a primary alkyl-halide.

Primary alkyl - halide undergo SN2 mechanism. This nucleophilic reaction needs to be a strong alkyl halide , such as 1-Bromopropane used  otherwise it will result to a reactive mechanism if a weak electrophile is used.

However, the critical and the main objective here is to Draw the major substitution product if the reaction proceeds in good yield. If no reaction is expected or yields will be poor, draw the starting material in the box. If a charged product is formed, be sure to draw the counterion.

The attached diagrams portraying this notions is shown in the attached file below.

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Given the following equation: Cu + 2 AgNO3 ---&gt; Cu(NO3)2 + 2
Temka [501]

Given the following equation; Cu + 2AgNO3 = Cu(NO3)2 + 2Ag, 48.97 grams of Cu are needed to react with 262g of AgNO3.

<h3>How to calculate mass of substances?</h3>

The mass of a substance can be calculated using the following steps:

Cu + 2AgNO3 = Cu(NO3)2 + 2Ag

1 mole of Cu react with 2 moles of AgNO3

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1.54 moles of AgNO3 will react with 0.77 moles of Cu.

mass of Cu = 0.77 × 63.5 = 48.97g

Therefore, given the following equation; Cu + 2AgNO3 = Cu(NO3)2 + 2Ag, 48.97 grams of Cu are needed to react with 262g of AgNO3.

Learn more about mass at: brainly.com/question/6876669

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