Suppose that y varies directly with x and y3 when x = 9. What is y when x = 18? y = [?]

Mathematics

1 answer:

exis [7]2 years ago

8 0

Answer:

y=6

Step-by-step explanation:

y=kx

3=9k

k=3/9

k=1/3

y=kx

y=1/3 × 18

y=6

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Please answer this in two minutes

solniwko [45]

Answer:

Step-by-step explanation:

a^2 + b^2 = c^2

(8sqrt(3))^2 + b^2 = 16^2

64 * 3 + b^2 = 256

192 + b^2 = 256

b^2 = 64

b = 8

The ratio of the lengths of the sides of this triangle is

8 : 8sqrt(3) : 16

which reduces to

1 : sqrt(3) : 2

This is the ratio of the lengths of the sides of a 30-60-90 triangle.

m<W = 30 deg

5 0

3 years ago

a toy rocket is launched from the top of a 48 foot hill. The rockets initial upward velocity is 32 feet per second and its heigh

sdas [7]

Answer:

t = 2.11 seconds

Step-by-step explanation:

A toy rocket is launched from the top of a 48 foot hill. The rockets initial upward velocity is 32 feet per second and its height h at any given second t is modeled by the equation:

$h=-16t^2+32t+48$

Let us assume that we need to find the time by it to reach the ground. It means h = 0

$-16t^2+32t+48=0$

The above is a quadratic equation. The value of t is given by :

$t=\dfrac{-b\pm \sqrt{b^2-2ac} }{2a}\\\\t=\dfrac{-b+ \sqrt{b^2-2ac} }{2a},\dfrac{-b- \sqrt{b^2-2ac} }{2a}\\\\t=\dfrac{-32+ \sqrt{(32)^2-2\times (-16)(8)} }{2\times (-16)},\dfrac{-32-\sqrt{(32)^{2}-2\times(-16)(8)}}{2\times(-16)}\\\\t=-0.11\ s, 2.11\ s$