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Anika [276]
3 years ago
5

3690 J of heat are added to a 21.5 g sample

Chemistry
1 answer:
Fiesta28 [93]3 years ago
6 0

Answer:

693K

Explanation:

The enthalpy change in the iron is 3690J

We now apply the formula for enthalpy change which is ΔH=mC∅ where ∅ is the temperature change, m the mass of the substance, and C the specific heat capacity for the substance.

ΔH in this case is 3690J.

Therefore 3690J=21.5g×0.449J/g.K×∅

as we are looking for ∅, we make it the subject of the formula.

∅=3690J/(21.5g×0.44J/g)

∅=390

Temperature=30°C +390

=420°+273

=693K

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A gas mixture contains 0.700 mol of N2, 0.300 mol of H2, and 0.400 mol of CH4. Calculate the pressure of the gas mixture and the
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Answer:

Pressure of the gas mixture: 4.30 atm

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To determine partial pressure we sum the total moles in order to find out the total pressure

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We apply the Ideal Gases Law

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We apply the mol the fraction for the partial pressure

Moles x gas / total moles = partial pressure x gas / total pressure

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Partial pressure H₂ = 0.21 . 4.30 atm = 0.91 atm

Mole fraction CH₄ → 0.400 /1.4 = 0.28

Partial pressure CH₄ = 0.28 . 4.30 atm =1.23 atm

7 0
3 years ago
Read 2 more answers
Convert 72g of O2 to moles
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Moles = mass / molar mass
molar mass of O2 is 32
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3 years ago
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