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BaLLatris [955]
3 years ago
8

A helium balloon has a volume of 25 L when the pressure is 1.551 ATM and the temperature is 20°C. The balloon is cooled at a con

stant pressure until the temperature is -11°C. What is the volume of the balloon at this stage?
Chemistry
1 answer:
Leona [35]3 years ago
4 0

Answer:

The balloon is cooled at a constant pressure until the temperature is -11°C. What is the volume of the balloon at this stage?

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How many moles of CaCO3 are needed to react with 12.5 mol SO2​
grandymaker [24]
<h3><u>Answer;</u></h3>

= 12.5 Moles of CaSO3

<h3><u>Explanation</u>;</h3>

The reaction between CaCO3 and SO2 is given by the equation.

CaCO3(s) + SO2(g) → CaSO3(aq) + CO2(g)

The mole ratio between CaCO3 and SO2 is 1 : 1;

1 mole of CaCO3 reacts with 1 mole SO2 to form CaSO3 and CO2

Therefore;

<em>12.5 moles of SO2 will require 12.5 moles of CaSO3</em>

7 0
3 years ago
Eading and
4vir4ik [10]

Answer: 25.8 g of Cl_2 will be produced from the decomposition of 73.4 g of AuCl_3

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} AuCl_3=\frac{73.4g}{303g/mol}=0.242moles

The balanced chemical reaction is:

2AuCl_3\rightarrow 2Au+3Cl_2  

According to stoichiometry :

2 moles of AuCl_3 produce =  3 moles of Cl_2

Thus 0.242 moles of  will produce= \frac{3}{2}\times 0.242=0.363mol of Cl_2

Mass of Cl_2= moles\times {\text {Molar mass}}=0.363mol\times 71g/mol=25.8g

Thus 25.8 g of Cl_2 will be produced from the decomposition of 73.4 g of AuCl_3

5 0
3 years ago
what mass of aluminium hydroxide is needed to decompose in order to produce 65.0 L of water at STP in stoichiometry?
pishuonlain [190]
Aluminium Hydroxide on decomposition produces Al₂O₃ and Water vapors. 

<span>                               2 Al(OH)</span>₃    →    Al₂O₃  +  3 H₂O


According to equation at STP,

       67.2 L (3 moles) of H₂O is produced by  =  78 g of Al(OH)₃
So,
                65.0 L of H₂O will be produced by  =  X g of Al(OH)₃

Solving for X,
                                 X  =  (65.0 L × 78 g) ÷ 67.2 L

                                 X  =  75.44 g of Al(OH)₂
Result:
           75.44 g of Al(OH)₂ is needed to decompose in order to produce 65.0 L of water at STP in stoichiometry
6 0
3 years ago
Read 2 more answers
Marcela dissolves 80.0 g of ammonium nitrate in 50.0 mL of water at room temperature and notes that the temperature of the solut
seraphim [82]

Answer: The correct answer is A

Explanation:

On addition of the ammonium nitrate to 50 ml of water the temperature decreases which means that reaction between the ammonium nitrate and water is an endothermic reaction.The value of \Delta H is positive for an endothermic reactions.

\Delta H>0

Entropy is a degree of randomness of the system.

On addition of the ammonium nitrate to water ammonium nitrate break down into ions which means that entropy is increased.

\Delta S>0

\Delta G=\Delta H-T\Delta S (Gibb's free energy)

Since, ammonium nitrate is getting dissolved in water which means that this reaction is spontaneous and \Delta G of spontaneous reaction is negative that is:

\Delta G

4 0
3 years ago
Read 2 more answers
Why is citric acid added to food?
kobusy [5.1K]

C is wrong, the real answer is B: to add tartness, and the reason why is because citric acid comes from jam, jellies, and more! And that is why the answer B is the correct answer.

Hope this helped!

Nate

(P.S. if you buy jams and real the ingredients, it will say "citric acid." :))

8 0
3 years ago
Read 2 more answers
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